{"id":2530,"date":"2021-10-04T05:10:28","date_gmt":"2021-10-04T05:10:28","guid":{"rendered":"http:\/\/stgwebsite.mindspark.in\/wordpress\/?page_id=2530"},"modified":"2022-01-02T07:17:36","modified_gmt":"2022-01-02T07:17:36","slug":"cube-root-of-19683-by-prime-factorisation-method","status":"publish","type":"page","link":"https:\/\/stgwebsite.mindspark.in\/studymaterial\/math-concepts\/cube-root-of-19683-by-prime-factorisation-method\/","title":{"rendered":"Cube root of 19683 by prime factorisation method"},"content":{"rendered":"

[et_pb_section fb_built=”1″ admin_label=”Section” module_class=”mainsec” _builder_version=”4.10.4″ _module_preset=”default” background_color=”#e0f2fd” z_index=”1″ custom_padding=”5px||5px||true|false” locked=”off” collapsed=”off” global_colors_info=”{}”][et_pb_row column_structure=”3_5,2_5″ custom_padding_last_edited=”on|phone” _builder_version=”4.10.6″ _module_preset=”default” background_color=”#FFFFFF” width=”100%” max_width=”1310px” custom_padding=”|51px|40px|51px|false|true” custom_padding_tablet=”” custom_padding_phone=”|40px|30px|40px|false|true” border_radii=”on|10px|10px|10px|10px” global_colors_info=”{}”][et_pb_column type=”3_5″ admin_label=”Column L” _builder_version=”4.9.10″ _module_preset=”default” global_colors_info=”{}”][et_pb_text admin_label=”Acute Angles
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Cube root of 19683 by prime factorisation method<\/strong><\/h1>\n

[\/et_pb_text][et_pb_text admin_label=”Text” _builder_version=”4.11.3″ _module_preset=”default” text_font_size=”16px” header_2_font=”|600|||||||” header_2_text_color=”#a01414″ header_3_font=”|600|||||||” header_3_text_color=”#7F7F7F” custom_padding=”15px|15px||4px|false|false” global_colors_info=”{}”]When the number is multiplied thrice by itself, the resultant number is the cube of that number. The number that is multiplied thrice is the cube root of that resultant number. It implies that the cube root is the inverse function of the cube. In this article, we are going to learn about the prime factorisation method to find the cube root of 19683.<\/p>\n

 <\/p>\n

CUBE ROOT OF 19683<\/strong><\/h2>\n

27 is the cube root of 19683. It means that when 27 is multiplied thrice by itself, we get the resultant number 19683.<\/p>\n

\u00a0<\/strong><\/p>\n

How to find the cube root?<\/strong><\/h3>\n

To find the cube root of a number, we will use the prime factorisation method. By evaluating the prime factors we will make the groups of threes of the same digits. Then we apply the cube root and choose one value from each group. After choosing the value, we will multiply those numbers. The result we get is the cube root of the required number.<\/p>\n

How to calculate the cube root of 19683?<\/strong><\/h3>\n

By using the prime factorization of 19683, we get- (3\u00d73\u00d73) \u00d7 (3\u00d73\u00d73) \u00d7 (3\u00d73\u00d73)<\/p>\n

We can also write it as – (33<\/sup>\u00d733<\/sup>\u00d733<\/sup>) = (3\u00d73\u00d73)3<\/sup><\/p>\n

When we apply the cube root on (3\u00d73\u00d73)3<\/sup>, we get the number 27.<\/p>\n

Therefore, 27 is the answer.[\/et_pb_text][et_pb_text disabled_on=”on|on|on” admin_label=”Sample Questions
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Questions<\/strong><\/p>\n

\u00a0When 19683 is divided by 27, we get the cube of which number?<\/span>
\nAns. When we divide 19683 by 27, we get the result 729.\u00a0<\/span>
\nWhen the prime factorisation is applied on 729, the prime factors we get- (3\u00d73\u00d73) \u00d7 (3\u00d73\u00d73)<\/span>
\nWhen we make the triplets of 3, we can write it as (3<\/span>3<\/span> \u00d7 3<\/span>3<\/span>) = (3\u00d73)<\/span>3<\/span>.<\/span>
\nOn applying the cube root on (3\u00d73)<\/span>3<\/span>, we get 9.<\/span>
\nHence, when 19683 is divided by 27, we get the cube of 9.<\/span>\n<\/div>\n<\/div>\n

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Related Concepts<\/h1>\n

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\n
Cube and Cube roots<\/a><\/div>\n
How to find the Cube root of a number easily?<\/a><\/div>\n
Cube root by long division method<\/a><\/div>\n<\/div>\n

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Frequently Asked Questions<\/h1>\n

Q1. Is the cube root of 19683 a perfect cube?<\/span><\/p>\n

Ans. We know that the cube root of 19683 is 27. The prime factors of 27 are (3 \u00d7 3 \u00d7 3) = (33<\/sup>).<\/span><\/p>\n

When we apply the cube root on 33<\/sup>, we get 3 as the cube root of 27. Therefore, 27 is a perfect cube of 3.<\/span><\/p>\n

Q2. How many real and complex cube roots does a real number have?<\/span><\/p>\n

Ans. A real number has one real cube root and two complex cube roots.<\/span><\/p>\n

Q3. When 19683 is divided by 27, we get the cube of which number?<\/span><\/p>\n

Ans. When we divide 19683 by 27, we get the result 729. <\/span><\/p>\n

When the prime factorisation is applied on 729, the prime factors we get- (3\u00d73\u00d73) \u00d7 (3\u00d73\u00d73)<\/span><\/p>\n

When we make the triplets of 3, we can write it as (33<\/sup> \u00d7 33<\/sup>) = (3\u00d73)3<\/sup>.<\/span><\/p>\n

On applying the cube root on (3\u00d73)3<\/sup>, we get 9<\/span><\/p>\n

Hence, when 19683 is divided by 27, we get the cube of 9.<\/span><\/p>\n

[\/et_pb_text][\/et_pb_column][\/et_pb_row][\/et_pb_section]<\/p>\n","protected":false},"excerpt":{"rendered":"

The value of the cube root of 19683 is 27. On performing the prime factorization on 19683, we get – (33 \u00d7 33 \u00d7 33) = (3 \u00d7 3 \u00d7 3)3.<\/p>\n","protected":false},"author":7,"featured_media":0,"parent":714,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"","meta":{"_et_pb_use_builder":"on","_et_pb_old_content":"","_et_gb_content_width":"","footnotes":""},"yoast_head":"\nCube root of 19683 by prime factorisation method - mydomain<\/title>\n<meta name=\"description\" content=\"The value of the cube root of 19683 is 27. 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