[\/et_pb_text][et_pb_text admin_label=”Text” _builder_version=”4.11.3″ _module_preset=”default” text_font_size=”16px” header_2_font=”|600|||||||” header_2_text_color=”#a01414″ header_3_font=”|600|||||||” header_3_text_color=”#898989″ custom_padding=”15px|15px||4px|false|false” global_colors_info=”{}”]<\/p>\n
What is a kite?<\/strong><\/h2>\nA kite is an irregular quadrilateral with 2 equal pairs of sides adjacent to\u00a0each other.Both the diagonals of the kite intersect each other at right angles.<\/p>\n
Here are some properties of a kite![\"\"](\"https:\/\/eistudymaterial.s3.amazonaws.com\/Untitfghled.png\")
<\/p>\n
\n- In the figure above, JK = KL and JM = LM, which means that adjacent sides of a kite are equal in length.<\/li>\n
- Diagonals\u00a0of a kite make an angle of 90 degrees at the point of intersection.<\/span><\/li>\n
- Angles between unequal sides are equal. Here, \u2220J = \u2220K<\/li>\n
- The longer diagonal divides the kite into one pair of congruent triangle.<\/strong><\/li>\n<\/ul>\n
<\/h2>\nWhat is the area of a kite formed by two perpendicular diagonals?<\/strong><\/h2>\nHalf the product of its diagonals gives the formula for the area of a kite<\/strong>. For example, if the diagonals of a kite are D1 and D2, then:<\/p>\nArea of kite<\/strong> = \u00bd D1 x D2<\/p>\n <\/p>\n
![\"\"](\"https:\/\/eistudymaterial.s3.amazonaws.com\/Untitf23ghled.png\")
<\/p>\n
<\/p>\n
Let us find the area of the kite PQRS.<\/p>\n
Here the diagonals are PR and QS<\/p>\n
Let diagonal PR be \u2018a\u2019 and diagonal QS be \u2018b.\u2019<\/p>\n
We know the diagonals of a kite bisect each other at right angles.<\/p>\n
So, in the figure, diagonal PR bisects diagonal QS.<\/p>\n
OQ = OS = OS\/2 =\u00a0 b\/2<\/p>\n
Area of the kite<\/strong> = sum of area of triangle PQR and PSR<\/p>\nArea of Triangle =\u00a0\u00bd b\u00d7h<\/p>\n
baseis\u2018a\u2019 and height is OQ = OS = OS\/2 =\u00a0 B\/2<\/p>\n
Area of triangle PQR =\u00a0\u00bd \u00a0x a x b\/2<\/p>\n
Area of triangle PSR=\u00a0\u00bd \u00a0x a x b\/2<\/p>\n
So, area of kite<\/strong> =\u00a0\u00bd \u00a0x a x b\/2+ \u00bd \u00a0x a x b\/2<\/p>\n= ab\/4\u00a0 + ab\/4<\/p>\n
= 2ab\/4 = 1\/2ab<\/span><\/p>\nSo, the formula for the area of the kite<\/strong>is \u00bd \u00a0x diagonal1 x diagonal2 = half the product of diagonals<\/p>\n <\/p>\n
An alternate method to find the area of a kite<\/strong><\/h3>\nConsider that you do not know the measure of the kite’s diagonals; how will you solve the area of kite questions<\/strong> without the diagonals if you do not know any alternate methods?<\/p>\nHere\u2019s the catch, you can use trigonometry to find the area of the kite formula with sides<\/strong> and their included angle. You can use the formula,<\/p>\nArea of kite = ab sinC<\/strong><\/p>\nwhere<\/p>\n
a and b denote the measure of unequal sides<\/p>\n
c is the internal angle between them<\/p>\n
and sin is the sine function in trigonometry<\/p>\n
<\/p>\n
Examples<\/strong><\/h3>\nExample 1<\/strong><\/p>\nHow can you prove the area of the kite is equal to the area of the rhombus?<\/p>\n
Solution<\/strong><\/p>\nWe explain to you how tocalculate the area of a rhombus by drawing two diagonals d1 and d2. These two diagonals are perpendicular to each other and bisect each other. So, one diagonal splits the rhombus into two equal triangles. Hence, the area of a rhombus is equal to the sum of the area of these two triangles.<\/p>\n
<\/p>\n
<\/p>\n
So, area of triangle ADC = area of triangle ABC = \u00bd \u00a0x d1 x d2\/2<\/p>\n
Area of rhombus = area of ADC + area of triangle ABC<\/p>\n
Area of rhombus = \u00bd x d1 x d2\/2 + \u00bd \u00a0x d1 x d2\/2<\/p>\n
= \u00bd x d1 x d2<\/p>\n
Considering this, the area of the kite and rhombus<\/strong> is the same.<\/p>\n <\/p>\n
Example 2<\/strong><\/p>\nCalculate the area of a kite with diagonals 24cm and 10cm<\/p>\n
Solution<\/strong><\/p>\nArea of kite =\u00a0 \u00bd x d1 x d2<\/p>\n
=\u00bd \u00a0x 24 x 10 cm2<\/sup><\/p>\n= 120 cm2<\/sup><\/p>\nTherefore, the area of kite = 120 cm2<\/sup><\/p>\n[\/et_pb_text][et_pb_text disabled_on=”on|on|on” admin_label=”Sample Questions
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Practice Multiple Choice Questions<\/h1>\n
[\/et_pb_text][et_pb_text disabled_on=”on|on|on” admin_label=”Question 1″ _builder_version=”4.11.1″ _module_preset=”default” background_color=”#FFFFFF” custom_padding=”25px|25px|25px|25px|true|true” border_radii=”on|15px|15px|15px|15px” border_width_all=”2px” border_color_all=”#000000″ border_width_top=”4px” border_color_top=”#E02B20″ disabled=”on” global_colors_info=”{}”]<\/p>\n
\n\nQuestions<\/strong><\/p>\nExample 1<\/b><\/p>\n
How can you prove the area of the kite is equal to the area of the rhombus?<\/span><\/p>\nSolution<\/b><\/p>\n
We explain to you how to calculate the area of a rhombus by drawing two diagonals d1 and d2. These two diagonals are perpendicular to each other and bisect each other. So, one diagonal splits the rhombus into two equal triangles. Hence, the area of a rhombus is equal to the sum of the area of these two triangles.<\/span><\/p>\nSo, area of triangle ADC = area of triangle ABC = <\/span>1<\/span>2<\/span> x d1 x <\/span>d2<\/span>2<\/span><\/p>\nArea of rhombus = area of ADC + area of triangle ABC<\/span><\/p>\nArea of rhombus = <\/span>1<\/span>2<\/span> x d1 x <\/span>d2<\/span>2<\/span> + <\/span>1<\/span>2<\/span> x d1 x <\/span>d2<\/span>2<\/span><\/p>\n= <\/span>1<\/span>2<\/span> x d1 x d2<\/span><\/p>\nConsidering this, the <\/span>area of the kite and rhombus<\/b> is the same.<\/span><\/p>\n <\/p>\n
Example 2<\/b><\/p>\n
Calculate the area of a kite with diagonals 24cm and 10cm<\/span><\/p>\nSolution<\/b><\/p>\n
Area of kite =\u00a0 <\/span>1<\/span>2<\/span> x d1 x d2<\/span><\/p>\n= <\/span>1<\/span>2<\/span> x 24 x 10 cm<\/span>2<\/span><\/p>\n= 120 cm<\/span>2<\/span><\/p>\nTherefore, <\/span>the area of kite = 120 cm<\/span>2<\/span><\/p>\n<\/div>\n<\/div>\n[\/et_pb_text][\/et_pb_column][et_pb_column type=”2_5″ module_id=”stickysideR” admin_label=”Column R” _builder_version=”4.10.4″ _module_preset=”default” background_color=”#fdefe0″ custom_padding=”25px|25px|25px|25px|true|true” sticky_position=”top” sticky_offset_top=”-280px” sticky_limit_top=”row” sticky_limit_bottom=”row” sticky_position_tablet=”none” sticky_position_phone=”none” sticky_position_last_edited=”on|desktop” sticky_limit_bottom_tablet=”” sticky_limit_bottom_phone=”” sticky_limit_bottom_last_edited=”on|phone” border_radii=”on|15px|15px|15px|15px” box_shadow_style=”preset3″ global_colors_info=”{}”][et_pb_image src=”https:\/\/eistudymaterial.s3.amazonaws.com\/1080×1080.png” alt=”Free Trial banner” title_text=”Mindspark Free Trial Banner” url=”https:\/\/mindspark.in\/free-trial” align=”center” module_class=”adsimg” _builder_version=”4.11.1″ _module_preset=”default” custom_padding=”||||false|false” border_radii=”on|10px|10px|10px|10px” locked=”off” global_colors_info=”{}” transform_styles__hover_enabled=”on|hover” transform_scale__hover_enabled=”on|hover” transform_translate__hover_enabled=”on|desktop” transform_rotate__hover_enabled=”on|desktop” transform_skew__hover_enabled=”on|desktop” transform_origin__hover_enabled=”on|desktop” transform_scale__hover=”102%|102%”][\/et_pb_image][et_pb_text admin_label=”Explore Other Topics
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Explore Other Topics<\/h1>\n
[\/et_pb_text][et_pb_text _builder_version=”4.10.7″ _module_preset=”default” text_line_height=”2.2em” link_font_size=”16px” custom_margin=”||0px||false|false” custom_padding=”10px|15px|10px|28px|true|false” locked=”off” global_colors_info=”{}”]<\/p>\n
\nGeometry<\/a><\/div>\nTrigonometry<\/a><\/div>\nOperations<\/a><\/div>\nNumbers<\/a><\/div>\n<\/div>\n[\/et_pb_text][et_pb_text admin_label=”Related Concepts
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Related Concepts<\/h1>\n
[\/et_pb_text][et_pb_text _builder_version=”4.13.1″ _module_preset=”default” text_line_height=”2.2em” link_font_size=”16px” custom_margin=”||0px||false|false” custom_padding=”10px|15px|10px|28px|true|false” locked=”off” global_colors_info=”{}”]<\/p>\n
\nMensuration Formula<\/a><\/div>\nArea of Rhombus<\/a><\/div>\n
<\/p>\n<\/h2>\nWhat is the area of a kite formed by two perpendicular diagonals?<\/strong><\/h2>\nHalf the product of its diagonals gives the formula for the area of a kite<\/strong>. For example, if the diagonals of a kite are D1 and D2, then:<\/p>\nArea of kite<\/strong> = \u00bd D1 x D2<\/p>\n <\/p>\n
<\/p>\n
<\/p>\n
Let us find the area of the kite PQRS.<\/p>\n
Here the diagonals are PR and QS<\/p>\n
Let diagonal PR be \u2018a\u2019 and diagonal QS be \u2018b.\u2019<\/p>\n
We know the diagonals of a kite bisect each other at right angles.<\/p>\n
So, in the figure, diagonal PR bisects diagonal QS.<\/p>\n
OQ = OS = OS\/2 =\u00a0 b\/2<\/p>\n
Area of the kite<\/strong> = sum of area of triangle PQR and PSR<\/p>\nArea of Triangle =\u00a0\u00bd b\u00d7h<\/p>\n
baseis\u2018a\u2019 and height is OQ = OS = OS\/2 =\u00a0 B\/2<\/p>\n
Area of triangle PQR =\u00a0\u00bd \u00a0x a x b\/2<\/p>\n
Area of triangle PSR=\u00a0\u00bd \u00a0x a x b\/2<\/p>\n
So, area of kite<\/strong> =\u00a0\u00bd \u00a0x a x b\/2+ \u00bd \u00a0x a x b\/2<\/p>\n= ab\/4\u00a0 + ab\/4<\/p>\n
= 2ab\/4 = 1\/2ab<\/span><\/p>\nSo, the formula for the area of the kite<\/strong>is \u00bd \u00a0x diagonal1 x diagonal2 = half the product of diagonals<\/p>\n <\/p>\n
An alternate method to find the area of a kite<\/strong><\/h3>\nConsider that you do not know the measure of the kite’s diagonals; how will you solve the area of kite questions<\/strong> without the diagonals if you do not know any alternate methods?<\/p>\nHere\u2019s the catch, you can use trigonometry to find the area of the kite formula with sides<\/strong> and their included angle. You can use the formula,<\/p>\nArea of kite = ab sinC<\/strong><\/p>\nwhere<\/p>\n
a and b denote the measure of unequal sides<\/p>\n
c is the internal angle between them<\/p>\n
and sin is the sine function in trigonometry<\/p>\n
<\/p>\n
Examples<\/strong><\/h3>\nExample 1<\/strong><\/p>\nHow can you prove the area of the kite is equal to the area of the rhombus?<\/p>\n
Solution<\/strong><\/p>\nWe explain to you how tocalculate the area of a rhombus by drawing two diagonals d1 and d2. These two diagonals are perpendicular to each other and bisect each other. So, one diagonal splits the rhombus into two equal triangles. Hence, the area of a rhombus is equal to the sum of the area of these two triangles.<\/p>\n
<\/p>\n
<\/p>\n
So, area of triangle ADC = area of triangle ABC = \u00bd \u00a0x d1 x d2\/2<\/p>\n
Area of rhombus = area of ADC + area of triangle ABC<\/p>\n
Area of rhombus = \u00bd x d1 x d2\/2 + \u00bd \u00a0x d1 x d2\/2<\/p>\n
= \u00bd x d1 x d2<\/p>\n
Considering this, the area of the kite and rhombus<\/strong> is the same.<\/p>\n <\/p>\n
Example 2<\/strong><\/p>\nCalculate the area of a kite with diagonals 24cm and 10cm<\/p>\n
Solution<\/strong><\/p>\nArea of kite =\u00a0 \u00bd x d1 x d2<\/p>\n
=\u00bd \u00a0x 24 x 10 cm2<\/sup><\/p>\n= 120 cm2<\/sup><\/p>\nTherefore, the area of kite = 120 cm2<\/sup><\/p>\n[\/et_pb_text][et_pb_text disabled_on=”on|on|on” admin_label=”Sample Questions
\n” _builder_version=”4.10.8″ _module_preset=”default” header_font=”|700|||||||” header_font_size=”28px” custom_padding=”|0px||4px|false|false” disabled=”on” global_colors_info=”{}”]<\/p>\n
Practice Multiple Choice Questions<\/h1>\n
[\/et_pb_text][et_pb_text disabled_on=”on|on|on” admin_label=”Question 1″ _builder_version=”4.11.1″ _module_preset=”default” background_color=”#FFFFFF” custom_padding=”25px|25px|25px|25px|true|true” border_radii=”on|15px|15px|15px|15px” border_width_all=”2px” border_color_all=”#000000″ border_width_top=”4px” border_color_top=”#E02B20″ disabled=”on” global_colors_info=”{}”]<\/p>\n
\n\nQuestions<\/strong><\/p>\nExample 1<\/b><\/p>\n
How can you prove the area of the kite is equal to the area of the rhombus?<\/span><\/p>\nSolution<\/b><\/p>\n
We explain to you how to calculate the area of a rhombus by drawing two diagonals d1 and d2. These two diagonals are perpendicular to each other and bisect each other. So, one diagonal splits the rhombus into two equal triangles. Hence, the area of a rhombus is equal to the sum of the area of these two triangles.<\/span><\/p>\nSo, area of triangle ADC = area of triangle ABC = <\/span>1<\/span>2<\/span> x d1 x <\/span>d2<\/span>2<\/span><\/p>\nArea of rhombus = area of ADC + area of triangle ABC<\/span><\/p>\nArea of rhombus = <\/span>1<\/span>2<\/span> x d1 x <\/span>d2<\/span>2<\/span> + <\/span>1<\/span>2<\/span> x d1 x <\/span>d2<\/span>2<\/span><\/p>\n= <\/span>1<\/span>2<\/span> x d1 x d2<\/span><\/p>\nConsidering this, the <\/span>area of the kite and rhombus<\/b> is the same.<\/span><\/p>\n <\/p>\n
Example 2<\/b><\/p>\n
Calculate the area of a kite with diagonals 24cm and 10cm<\/span><\/p>\nSolution<\/b><\/p>\n
Area of kite =\u00a0 <\/span>1<\/span>2<\/span> x d1 x d2<\/span><\/p>\n= <\/span>1<\/span>2<\/span> x 24 x 10 cm<\/span>2<\/span><\/p>\n= 120 cm<\/span>2<\/span><\/p>\nTherefore, <\/span>the area of kite = 120 cm<\/span>2<\/span><\/p>\n<\/div>\n<\/div>\n[\/et_pb_text][\/et_pb_column][et_pb_column type=”2_5″ module_id=”stickysideR” admin_label=”Column R” _builder_version=”4.10.4″ _module_preset=”default” background_color=”#fdefe0″ custom_padding=”25px|25px|25px|25px|true|true” sticky_position=”top” sticky_offset_top=”-280px” sticky_limit_top=”row” sticky_limit_bottom=”row” sticky_position_tablet=”none” sticky_position_phone=”none” sticky_position_last_edited=”on|desktop” sticky_limit_bottom_tablet=”” sticky_limit_bottom_phone=”” sticky_limit_bottom_last_edited=”on|phone” border_radii=”on|15px|15px|15px|15px” box_shadow_style=”preset3″ global_colors_info=”{}”][et_pb_image src=”https:\/\/eistudymaterial.s3.amazonaws.com\/1080×1080.png” alt=”Free Trial banner” title_text=”Mindspark Free Trial Banner” url=”https:\/\/mindspark.in\/free-trial” align=”center” module_class=”adsimg” _builder_version=”4.11.1″ _module_preset=”default” custom_padding=”||||false|false” border_radii=”on|10px|10px|10px|10px” locked=”off” global_colors_info=”{}” transform_styles__hover_enabled=”on|hover” transform_scale__hover_enabled=”on|hover” transform_translate__hover_enabled=”on|desktop” transform_rotate__hover_enabled=”on|desktop” transform_skew__hover_enabled=”on|desktop” transform_origin__hover_enabled=”on|desktop” transform_scale__hover=”102%|102%”][\/et_pb_image][et_pb_text admin_label=”Explore Other Topics
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Explore Other Topics<\/h1>\n
[\/et_pb_text][et_pb_text _builder_version=”4.10.7″ _module_preset=”default” text_line_height=”2.2em” link_font_size=”16px” custom_margin=”||0px||false|false” custom_padding=”10px|15px|10px|28px|true|false” locked=”off” global_colors_info=”{}”]<\/p>\n
\nGeometry<\/a><\/div>\nTrigonometry<\/a><\/div>\nOperations<\/a><\/div>\nNumbers<\/a><\/div>\n<\/div>\n[\/et_pb_text][et_pb_text admin_label=”Related Concepts
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Related Concepts<\/h1>\n
[\/et_pb_text][et_pb_text _builder_version=”4.13.1″ _module_preset=”default” text_line_height=”2.2em” link_font_size=”16px” custom_margin=”||0px||false|false” custom_padding=”10px|15px|10px|28px|true|false” locked=”off” global_colors_info=”{}”]<\/p>\n
\nMensuration Formula<\/a><\/div>\nArea of Rhombus<\/a><\/div>\n
Half the product of its diagonals gives the formula for the area of a kite<\/strong>. For example, if the diagonals of a kite are D1 and D2, then:<\/p>\n Area of kite<\/strong> = \u00bd D1 x D2<\/p>\n <\/p>\n <\/p>\n Let us find the area of the kite PQRS.<\/p>\n Here the diagonals are PR and QS<\/p>\n Let diagonal PR be \u2018a\u2019 and diagonal QS be \u2018b.\u2019<\/p>\n We know the diagonals of a kite bisect each other at right angles.<\/p>\n So, in the figure, diagonal PR bisects diagonal QS.<\/p>\n OQ = OS = OS\/2 =\u00a0 b\/2<\/p>\n Area of the kite<\/strong> = sum of area of triangle PQR and PSR<\/p>\n Area of Triangle =\u00a0\u00bd b\u00d7h<\/p>\n baseis\u2018a\u2019 and height is OQ = OS = OS\/2 =\u00a0 B\/2<\/p>\n Area of triangle PQR =\u00a0\u00bd \u00a0x a x b\/2<\/p>\n Area of triangle PSR=\u00a0\u00bd \u00a0x a x b\/2<\/p>\n So, area of kite<\/strong> =\u00a0\u00bd \u00a0x a x b\/2+ \u00bd \u00a0x a x b\/2<\/p>\n = ab\/4\u00a0 + ab\/4<\/p>\n = 2ab\/4 = 1\/2ab<\/span><\/p>\n So, the formula for the area of the kite<\/strong>is \u00bd \u00a0x diagonal1 x diagonal2 = half the product of diagonals<\/p>\n <\/p>\n Consider that you do not know the measure of the kite’s diagonals; how will you solve the area of kite questions<\/strong> without the diagonals if you do not know any alternate methods?<\/p>\n Here\u2019s the catch, you can use trigonometry to find the area of the kite formula with sides<\/strong> and their included angle. You can use the formula,<\/p>\n Area of kite = ab sinC<\/strong><\/p>\n where<\/p>\n a and b denote the measure of unequal sides<\/p>\n c is the internal angle between them<\/p>\n and sin is the sine function in trigonometry<\/p>\n <\/p>\n Example 1<\/strong><\/p>\n How can you prove the area of the kite is equal to the area of the rhombus?<\/p>\n Solution<\/strong><\/p>\n We explain to you how tocalculate the area of a rhombus by drawing two diagonals d1 and d2. These two diagonals are perpendicular to each other and bisect each other. So, one diagonal splits the rhombus into two equal triangles. Hence, the area of a rhombus is equal to the sum of the area of these two triangles.<\/p>\n <\/p>\n So, area of triangle ADC = area of triangle ABC = \u00bd \u00a0x d1 x d2\/2<\/p>\n Area of rhombus = area of ADC + area of triangle ABC<\/p>\n Area of rhombus = \u00bd x d1 x d2\/2 + \u00bd \u00a0x d1 x d2\/2<\/p>\n = \u00bd x d1 x d2<\/p>\n Considering this, the area of the kite and rhombus<\/strong> is the same.<\/p>\n <\/p>\n Example 2<\/strong><\/p>\n Calculate the area of a kite with diagonals 24cm and 10cm<\/p>\n Solution<\/strong><\/p>\n Area of kite =\u00a0 \u00bd x d1 x d2<\/p>\n =\u00bd \u00a0x 24 x 10 cm2<\/sup><\/p>\n = 120 cm2<\/sup><\/p>\n Therefore, the area of kite = 120 cm2<\/sup><\/p>\n [\/et_pb_text][et_pb_text disabled_on=”on|on|on” admin_label=”Sample Questions [\/et_pb_text][et_pb_text disabled_on=”on|on|on” admin_label=”Question 1″ _builder_version=”4.11.1″ _module_preset=”default” background_color=”#FFFFFF” custom_padding=”25px|25px|25px|25px|true|true” border_radii=”on|15px|15px|15px|15px” border_width_all=”2px” border_color_all=”#000000″ border_width_top=”4px” border_color_top=”#E02B20″ disabled=”on” global_colors_info=”{}”]<\/p>\n Questions<\/strong><\/p>\n Example 1<\/b><\/p>\n How can you prove the area of the kite is equal to the area of the rhombus?<\/span><\/p>\n Solution<\/b><\/p>\n We explain to you how to calculate the area of a rhombus by drawing two diagonals d1 and d2. These two diagonals are perpendicular to each other and bisect each other. So, one diagonal splits the rhombus into two equal triangles. Hence, the area of a rhombus is equal to the sum of the area of these two triangles.<\/span><\/p>\n So, area of triangle ADC = area of triangle ABC = <\/span>1<\/span>2<\/span> x d1 x <\/span>d2<\/span>2<\/span><\/p>\n Area of rhombus = area of ADC + area of triangle ABC<\/span><\/p>\n Area of rhombus = <\/span>1<\/span>2<\/span> x d1 x <\/span>d2<\/span>2<\/span> + <\/span>1<\/span>2<\/span> x d1 x <\/span>d2<\/span>2<\/span><\/p>\n = <\/span>1<\/span>2<\/span> x d1 x d2<\/span><\/p>\n Considering this, the <\/span>area of the kite and rhombus<\/b> is the same.<\/span><\/p>\n <\/p>\n Example 2<\/b><\/p>\n Calculate the area of a kite with diagonals 24cm and 10cm<\/span><\/p>\n Solution<\/b><\/p>\n Area of kite =\u00a0 <\/span>1<\/span>2<\/span> x d1 x d2<\/span><\/p>\n = <\/span>1<\/span>2<\/span> x 24 x 10 cm<\/span>2<\/span><\/p>\n = 120 cm<\/span>2<\/span><\/p>\n Therefore, <\/span>the area of kite = 120 cm<\/span>2<\/span><\/p>\n<\/div>\n<\/div>\n [\/et_pb_text][\/et_pb_column][et_pb_column type=”2_5″ module_id=”stickysideR” admin_label=”Column R” _builder_version=”4.10.4″ _module_preset=”default” background_color=”#fdefe0″ custom_padding=”25px|25px|25px|25px|true|true” sticky_position=”top” sticky_offset_top=”-280px” sticky_limit_top=”row” sticky_limit_bottom=”row” sticky_position_tablet=”none” sticky_position_phone=”none” sticky_position_last_edited=”on|desktop” sticky_limit_bottom_tablet=”” sticky_limit_bottom_phone=”” sticky_limit_bottom_last_edited=”on|phone” border_radii=”on|15px|15px|15px|15px” box_shadow_style=”preset3″ global_colors_info=”{}”][et_pb_image src=”https:\/\/eistudymaterial.s3.amazonaws.com\/1080×1080.png” alt=”Free Trial banner” title_text=”Mindspark Free Trial Banner” url=”https:\/\/mindspark.in\/free-trial” align=”center” module_class=”adsimg” _builder_version=”4.11.1″ _module_preset=”default” custom_padding=”||||false|false” border_radii=”on|10px|10px|10px|10px” locked=”off” global_colors_info=”{}” transform_styles__hover_enabled=”on|hover” transform_scale__hover_enabled=”on|hover” transform_translate__hover_enabled=”on|desktop” transform_rotate__hover_enabled=”on|desktop” transform_skew__hover_enabled=”on|desktop” transform_origin__hover_enabled=”on|desktop” transform_scale__hover=”102%|102%”][\/et_pb_image][et_pb_text admin_label=”Explore Other Topics [\/et_pb_text][et_pb_text _builder_version=”4.10.7″ _module_preset=”default” text_line_height=”2.2em” link_font_size=”16px” custom_margin=”||0px||false|false” custom_padding=”10px|15px|10px|28px|true|false” locked=”off” global_colors_info=”{}”]<\/p>\n [\/et_pb_text][et_pb_text admin_label=”Related Concepts [\/et_pb_text][et_pb_text _builder_version=”4.13.1″ _module_preset=”default” text_line_height=”2.2em” link_font_size=”16px” custom_margin=”||0px||false|false” custom_padding=”10px|15px|10px|28px|true|false” locked=”off” global_colors_info=”{}”]<\/p>\n<\/p>\nAn alternate method to find the area of a kite<\/strong><\/h3>\n
Examples<\/strong><\/h3>\n
<\/p>\n
\n” _builder_version=”4.10.8″ _module_preset=”default” header_font=”|700|||||||” header_font_size=”28px” custom_padding=”|0px||4px|false|false” disabled=”on” global_colors_info=”{}”]<\/p>\nPractice Multiple Choice Questions<\/h1>\n
\n” _builder_version=”4.9.11″ _module_preset=”default” header_font=”|700|||||||” header_font_size=”25px” text_orientation=”center” custom_margin=”0px||0px||true|false” custom_padding=”8px|15px|0px|15px|false|true” locked=”off” global_colors_info=”{}”]<\/p>\nExplore Other Topics<\/h1>\n
\n” _builder_version=”4.9.11″ _module_preset=”default” header_font=”|700|||||||” header_font_size=”25px” text_orientation=”center” custom_margin=”0px||0px||true|false” custom_padding=”8px|15px|0px|15px|false|true” locked=”off” global_colors_info=”{}”]<\/p>\nRelated Concepts<\/h1>\n