[et_pb_section fb_built=”1″ admin_label=”Section” module_class=”mainsec” _builder_version=”4.10.4″ _module_preset=”default” background_color=”#e0f2fd” z_index=”1″ custom_padding=”5px||5px||true|false” locked=”off” collapsed=”off” global_colors_info=”{}”][et_pb_row column_structure=”3_5,2_5″ custom_padding_last_edited=”on|phone” _builder_version=”4.10.8″ _module_preset=”default” background_color=”#FFFFFF” width=”100%” max_width=”1310px” custom_padding=”|51px|40px|51px|false|true” custom_padding_tablet=”” custom_padding_phone=”|40px|30px|40px|false|true” border_radii=”on|10px|10px|10px|10px” global_colors_info=”{}”][et_pb_column type=”3_5″ admin_label=”Column L” _builder_version=”4.9.10″ _module_preset=”default” global_colors_info=”{}”][et_pb_text admin_label=”Acute Angles
\n” _builder_version=”4.11.3″ _module_preset=”default” header_font=”|700|||||||” header_text_align=”left” header_font_size=”50px” header_line_height=”1.18em” custom_padding=”|0px||4px|false|false” header_font_size_tablet=”” header_font_size_phone=”35px” header_font_size_last_edited=”on|phone” global_colors_info=”{}”]<\/p>\n
[\/et_pb_text][et_pb_text admin_label=”Text” _builder_version=”4.11.3″ _module_preset=”default” text_font_size=”16px” header_2_font=”|600|||||||” header_2_text_color=”#a01414″ header_3_font=”|600|||||||” custom_padding=”2px|15px|1px|4px|false|false” global_colors_info=”{}”]<\/p>\n
<\/span><\/p>\n <\/span><\/p>\n A semi-circle is half a circle. When a straight line is drawn through a circle in such a manner that the line passes through the centre of the circle, then such a line would cut the circle into exactly two equal halves, and each half is a semicircle. A common example of a semicircle is the protractor in our geometry box.\u00a0<\/span><\/p>\n Let us try to understand how to calculate the area of a semicircle in this article.\u00a0<\/span><\/p>\n <\/span><\/p>\n <\/span><\/p>\n <\/span><\/p>\n The area of a semicircle is the number of square units that can be filled within a semicircle.\u00a0 A semicircle is half of a circle. Hence, the area of a semicircle is half the area of a circle.\u00a0<\/span><\/p>\n [\/et_pb_text][et_pb_image src=”https:\/\/eistudymaterial.s3.amazonaws.com\/Area-of-semicircle.png” title_text=”Area of semicircle” align=”center” _builder_version=”4.11.3″ _module_preset=”default” min_height=”220px” global_colors_info=”{}”][\/et_pb_image][et_pb_text admin_label=”Text” _builder_version=”4.11.3″ _module_preset=”default” text_font_size=”16px” header_2_font=”|600|||||||” header_2_text_color=”#a01414″ header_3_font=”|600|||||||” custom_padding=”2px|15px|1px|4px|false|false” global_colors_info=”{}”]<\/p>\n The radius in the above semicircle is the distance between any point on the arc BDC and the midpoint A.<\/p>\n Hence, AC = AB = AD = Radius.<\/p>\n We know that the area of a circle with radius\u00a0 \u2018r\u2019 is \\left(\\pi \\times r^{2}\\right) \\text { unit }^{2}<\/span>.<\/p>\n Since a semicircle is a half circle,<\/p>\n <\/span><\/p>\n The area of a semicircle with a radius \u2018r\u2019 is \\left(\\frac{1}{2} \\times \\pi \\times r^{2}\\right)<\/span>\\text { unit }^{2}<\/span>and \\pi<\/span> is constant at 3.14 or \\frac{22}{7}<\/span>\u00a0<\/span><\/p>\n <\/span><\/p>\n <\/span><\/p>\n Solution:<\/b><\/p>\n the area of a semicircle is \\frac{1}{2} \\times \\pi \\times r^{2}<\/span> \\text { unit }^{2}<\/span><\/span>. In the given question, r = 9 cm<\/span><\/p>\n Substituting the value of r = 9 cm in the formula,<\/span><\/p>\n Area of semicircle = =\\frac{1}{2} \\times \\frac{22}{7} \\times 9^{2} \\mathrm{~cm}^{2}<\/span><\/span><\/p>\n \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0=127.29 \\mathrm{~cm}^{2}<\/span><\/span><\/p>\n <\/span><\/p>\n <\/span><\/p>\n 2.<\/strong> <\/b><\/span>Mr.C buys a circular clock where the length of the minute hand is 21 cm. Calculate the area covered by the minute hand in 30 minutes.<\/b><\/p>\n <\/b><\/p>\n Solution:<\/b><\/p>\n It is given that the length of the minute hand is 21 cm. This is the radius of the circular clock. So, to calculate the area covered by the minute hand in 30 minutes, we have to calculate the area of the semicircle.<\/span><\/p>\n The area of a semicircle is \\frac{1}{2} \\times \\pi \\times r^{2}<\/span> \\text { unit }^{2}<\/span>, where r = radius.<\/span><\/p>\n Using the value of r = 21 cm in the formula, Area of semicircle = \\frac{1}{2} \\times \\frac{22}{7} \\times 21^{2} \\mathrm{~cm}^{2}<\/span><\/span><\/p>\n \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 =693 \\mathrm{~cm}^{2}<\/span><\/span><\/p>\n <\/span><\/p>\n <\/span><\/p>\n 3. Mr. X and Mr. Y are hired to clean a circular park. The distance from the middle of the park to any point on the park\u2019s boundary is 350 meters. Mr. X and Mr. Y each agree to clean exactly half the park. Calculate the area of the park cleaned by Mr.X.<\/strong> <\/strong><\/span><\/p>\n Solution:\u00a0 <\/b><\/strong><\/span>It is given that the distance between the centre to any point on the park\u2019s boundary is 350 m. This is the radius of the park. Since Mr. X is cleaning only half of the park, we have to calculate the area of the semicircle.<\/span><\/p>\n <\/span><\/p>\n The area of a semicircle is \\frac{1}{2} \\times \\pi \\times 1^{2}<\/span> \\text { unit }^{2}<\/span>, where r = radius.<\/span><\/p>\n Substituting the value of r = 350 m in the formula,<\/span><\/span><\/p>\n <\/span><\/p>\n Area of semicircle =\\frac{1}{2} \\times \\frac{22}{7} \\times 350^{2} \\mathrm{~m}^{2}<\/span><\/span><\/p>\n \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0=1,92,500 \\mathrm{~m}^{2}<\/span><\/span><\/p>\n <\/strong><\/span><\/p>\n <\/strong><\/span><\/p>\n [\/et_pb_text][et_pb_text _builder_version=”4.11.3″ _module_preset=”default” custom_padding=”||56px|||” global_colors_info=”{}”][\/et_pb_text][\/et_pb_column][et_pb_column type=”2_5″ module_id=”stickysideR” admin_label=”Column R” _builder_version=”4.10.4″ _module_preset=”default” background_color=”#fdefe0″ custom_padding=”25px|25px|25px|25px|true|true” sticky_position=”top” sticky_offset_top=”-280px” sticky_limit_top=”row” sticky_limit_bottom=”row” sticky_position_tablet=”none” sticky_position_phone=”none” sticky_position_last_edited=”on|desktop” sticky_limit_bottom_tablet=”” sticky_limit_bottom_phone=”” sticky_limit_bottom_last_edited=”on|phone” border_radii=”on|15px|15px|15px|15px” box_shadow_style=”preset3″ global_colors_info=”{}”][et_pb_image src=”https:\/\/eistudymaterial.s3.amazonaws.com\/1080×1080.png” alt=”Free Trial banner” title_text=”Mindspark Free Trial Banner” url=”https:\/\/mindspark.in\/free-trial” align=”center” module_class=”adsimg” _builder_version=”4.11.1″ _module_preset=”default” custom_padding=”||||false|false” border_radii=”on|10px|10px|10px|10px” global_colors_info=”{}” transform_styles__hover_enabled=”on|hover” transform_scale__hover_enabled=”on|hover” transform_translate__hover_enabled=”on|desktop” transform_rotate__hover_enabled=”on|desktop” transform_skew__hover_enabled=”on|desktop” transform_origin__hover_enabled=”on|desktop” transform_scale__hover=”102%|102%”][\/et_pb_image][et_pb_text admin_label=”Explore Other Topics [\/et_pb_text][et_pb_text _builder_version=”4.10.7″ _module_preset=”default” text_line_height=”2.2em” link_font_size=”16px” custom_margin=”||0px||false|false” custom_padding=”10px|15px|10px|28px|true|false” locked=”off” global_colors_info=”{}”]<\/p>\n [\/et_pb_text][et_pb_text admin_label=”Related Concepts [\/et_pb_text][et_pb_text _builder_version=”4.13.1″ _module_preset=”default” text_line_height=”2.2em” link_font_size=”16px” custom_margin=”||0px||false|false” custom_padding=”10px|15px|10px|28px|true|false” locked=”off” global_colors_info=”{}”]<\/p>\n [\/et_pb_text][\/et_pb_column][\/et_pb_row][et_pb_row admin_label=”Row for space” _builder_version=”4.10.6″ _module_preset=”default” locked=”off” global_colors_info=”{}”][et_pb_column type=”4_4″ _builder_version=”4.9.11″ _module_preset=”default” global_colors_info=”{}”][et_pb_divider show_divider=”off” _builder_version=”4.10.4″ _module_preset=”default” global_colors_info=”{}”][\/et_pb_divider][\/et_pb_column][\/et_pb_row][\/et_pb_section][et_pb_section fb_built=”1″ admin_label=”banner and faq Section” module_class=”mainsec2″ _builder_version=”4.10.4″ _module_preset=”default” custom_padding=”40px||0px||false|false” global_colors_info=”{}”][et_pb_row use_custom_gutter=”on” gutter_width=”1″ make_equal=”on” disabled_on=”on|on|off” admin_label=”banner Row” _builder_version=”4.10.4″ _module_preset=”default” background_color=”#fff7d6″ width=”100%” max_width=”1310px” height=”134px” custom_margin=”||50px||false|false” custom_padding=”12px||12px||true|false” border_radii=”on|11px|11px|11px|11px” locked=”off” collapsed=”off” global_colors_info=”{}”][et_pb_column type=”4_4″ _builder_version=”4.9.10″ _module_preset=”default” global_colors_info=”{}”][et_pb_image src=”https:\/\/stgwebsite.mindspark.in\/wordpress\/wp-content\/uploads\/2021\/08\/calloutImage.png” title_text=”calloutImage” show_bottom_space=”off” admin_label=”Image” module_class=”img1″ _builder_version=”4.10.8″ _module_preset=”default” width=”25px” height=”60px” custom_padding=”2px||2px||true|false” global_colors_info=”{}”][\/et_pb_image][et_pb_text module_class=”ftstyle” _builder_version=”4.9.10″ _module_preset=”default” text_orientation=”center” global_colors_info=”{}”]<\/p>\nArea of a semicircle<\/span><\/h2>\n
Formula:<\/span><\/h2>\n
Examples:<\/span><\/h2>\n
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\n” _builder_version=”4.9.11″ _module_preset=”default” header_font=”|700|||||||” header_font_size=”25px” text_orientation=”center” custom_margin=”0px||0px||true|false” custom_padding=”8px|15px|0px|15px|false|true” locked=”off” global_colors_info=”{}”]<\/p>\nExplore Other Topics<\/h1>\n
\n” _builder_version=”4.9.11″ _module_preset=”default” header_font=”|700|||||||” header_font_size=”25px” text_orientation=”center” custom_margin=”0px||0px||true|false” custom_padding=”8px|15px|0px|15px|false|true” locked=”off” global_colors_info=”{}”]<\/p>\nRelated Concepts<\/h1>\n