{"id":4484,"date":"2021-11-25T13:20:05","date_gmt":"2021-11-25T13:20:05","guid":{"rendered":"https:\/\/stgwebsite.mindspark.in\/studymaterial\/?page_id=4484"},"modified":"2022-01-02T13:37:34","modified_gmt":"2022-01-02T13:37:34","slug":"curved-surface-area-of-cylinder-derivation-formula-and-examples","status":"publish","type":"page","link":"https:\/\/stgwebsite.mindspark.in\/studymaterial\/math-concepts\/curved-surface-area-of-cylinder-derivation-formula-and-examples\/","title":{"rendered":"Curved Surface Area of Cylinder \u2013 Derivation, Formula and Examples"},"content":{"rendered":"<p>[et_pb_section fb_built=&#8221;1&#8243; admin_label=&#8221;Section&#8221; module_class=&#8221;mainsec&#8221; _builder_version=&#8221;4.10.4&#8243; _module_preset=&#8221;default&#8221; background_color=&#8221;#e0f2fd&#8221; z_index=&#8221;1&#8243; custom_padding=&#8221;5px||5px||true|false&#8221; locked=&#8221;off&#8221; collapsed=&#8221;off&#8221; global_colors_info=&#8221;{}&#8221;][et_pb_row column_structure=&#8221;3_5,2_5&#8243; custom_padding_last_edited=&#8221;on|phone&#8221; _builder_version=&#8221;4.10.8&#8243; _module_preset=&#8221;default&#8221; background_color=&#8221;#FFFFFF&#8221; width=&#8221;100%&#8221; max_width=&#8221;1310px&#8221; custom_padding=&#8221;|51px|40px|51px|false|true&#8221; custom_padding_tablet=&#8221;&#8221; custom_padding_phone=&#8221;|40px|30px|40px|false|true&#8221; border_radii=&#8221;on|10px|10px|10px|10px&#8221; global_colors_info=&#8221;{}&#8221;][et_pb_column type=&#8221;3_5&#8243; admin_label=&#8221;Column L&#8221; _builder_version=&#8221;4.9.10&#8243; _module_preset=&#8221;default&#8221; global_colors_info=&#8221;{}&#8221;][et_pb_text admin_label=&#8221;Acute Angles<br \/>\n&#8221; _builder_version=&#8221;4.11.3&#8243; _module_preset=&#8221;default&#8221; header_font=&#8221;|700|||||||&#8221; header_text_align=&#8221;left&#8221; header_font_size=&#8221;50px&#8221; header_line_height=&#8221;1.18em&#8221; custom_padding=&#8221;|0px||4px|false|false&#8221; header_font_size_tablet=&#8221;&#8221; header_font_size_phone=&#8221;35px&#8221; header_font_size_last_edited=&#8221;on|phone&#8221; global_colors_info=&#8221;{}&#8221;]<\/p>\n<h1>Curved Surface Area of Cylinder \u2013 Derivation, Formula and Examples<\/h1>\n<p>[\/et_pb_text][et_pb_text admin_label=&#8221;Text&#8221; _builder_version=&#8221;4.13.1&#8243; _module_preset=&#8221;default&#8221; text_font_size=&#8221;16px&#8221; header_2_font=&#8221;|600|||||||&#8221; header_2_text_color=&#8221;#a01414&#8243; header_3_font=&#8221;|600|||||||&#8221; custom_padding=&#8221;15px|15px|54px|4px|false|false&#8221; global_colors_info=&#8221;{}&#8221;]<\/p>\n<h2><b>What is a Cylinder?<\/b><b><\/b><\/h2>\n<p><span style=\"font-weight: 400;\">A cylinder is a 3D solid object with two parallel circular bases at both ends of the cylindrical shape. The radius of the circular bases of the cylinder corresponds to the radius (r) of the cylinder. The axis connecting the two circular bases denotes the height (h) of the cylinder.\u00a0<\/span><\/p>\n<p style=\"text-align: center;\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/eistudymaterial.s3.amazonaws.com\/CSA-of-Cylinder-Final-01-221x300.png\" width=\"221\" height=\"300\" alt=\"\" class=\"wp-image-4490 alignnone size-medium\" srcset=\"https:\/\/eistudymaterial.s3.amazonaws.com\/CSA-of-Cylinder-Final-01-221x300.png 221w, https:\/\/eistudymaterial.s3.amazonaws.com\/CSA-of-Cylinder-Final-01.png 233w\" sizes=\"(max-width: 221px) 100vw, 221px\" \/><\/p>\n<h2><\/h2>\n<h2><b>The Surface Area of a Cylinder<\/b><\/h2>\n<p>In terms of a cylinder, it is imperative to differentiate between the total surface area and the lateral surface area. In layman terms, people tend to relate surface area to total surface area. Hence, making it essential to mark the difference between the two.<\/p>\n<p>If someone asks you to find the surface area, they are probably asking you to figure out the TSA of the cylinder. But before diving into the derivation of the formula of CSA and TSA of a cylinder, you must be well aware of the radius, diameter, height, and \u03c0. All these determinants play a crucial role in finding the surface area of a cylinder.<\/p>\n<p>As defined earlier, the radius (r) emerges from the two circular faces while the height (h) emerges from the cylindrical body. Therefore, the surface area calculation involves the area of the two circles, the height of the cylinder, and \u03c0.<b><br \/><\/b><\/p>\n<p>&nbsp;<\/p>\n<h2><b>Curved Surface Area of a Cylinder<\/b><\/h2>\n<p><span style=\"font-weight: 400;\">The curved surface area of a cylinder is known as the area of the curved surface that connects the two circular bases.\u00a0<\/span><\/p>\n<p style=\"text-align: center;\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/eistudymaterial.s3.amazonaws.com\/CSA-of-Cylinder-Final-02-300x152.png\" width=\"300\" height=\"152\" alt=\"\" class=\"wp-image-4491 alignnone size-medium\" srcset=\"https:\/\/eistudymaterial.s3.amazonaws.com\/CSA-of-Cylinder-Final-02-300x152.png 300w, https:\/\/eistudymaterial.s3.amazonaws.com\/CSA-of-Cylinder-Final-02-480x243.png 480w, https:\/\/eistudymaterial.s3.amazonaws.com\/CSA-of-Cylinder-Final-02.png 768w\" sizes=\"(max-width: 300px) 100vw, 300px\" \/><\/p>\n<p><span style=\"font-weight: 400;\">You can also obtain the CSA of a cylinder after excluding the circular areas from the total area of the cylinder.\u00a0<\/span><\/p>\n<p><span style=\"font-weight: 400;\">\u00a0<\/span><\/p>\n<h3><b>CSA of a Cylinder formula<\/b><\/h3>\n<p><span style=\"font-weight: 400;\">Considering the height of the cylinder as \u2018h\u2019 and radius of the cylinder as \u2018r\u2019, we have the formula of the CSA of the cylinder as 2\u03c0rh square units.<\/span><\/p>\n<p>&nbsp;<\/p>\n<h3><b>Derivation of the Curved Surface Area of a Cylinder\u00a0<\/b><b><\/b><\/h3>\n<p><span style=\"font-weight: 400;\">Consider a solid cylindrical shape of radius \u2018r\u2019 and height \u2018h\u2019. To obtain the formula of the curved surface of the cylindrical body, take a rectangular sheet and wrap it around this cylinder. Cut the edges from the top and bottom to match the shape of this cylinder. The area of this rectangular piece of paper is the curved surface of the cylinder.\u00a0<\/span><\/p>\n<p><span style=\"font-weight: 400;\"><\/span><\/p>\n<p style=\"text-align: center;\"><span style=\"font-weight: 400;\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/eistudymaterial.s3.amazonaws.com\/CSA-of-Cylinder-Final-03-300x100.png\" width=\"351\" height=\"117\" alt=\"\" class=\"wp-image-4492 alignnone size-medium\" srcset=\"https:\/\/eistudymaterial.s3.amazonaws.com\/CSA-of-Cylinder-Final-03-300x100.png 300w, https:\/\/eistudymaterial.s3.amazonaws.com\/CSA-of-Cylinder-Final-03-768x256.png 768w, https:\/\/eistudymaterial.s3.amazonaws.com\/CSA-of-Cylinder-Final-03-480x160.png 480w, https:\/\/eistudymaterial.s3.amazonaws.com\/CSA-of-Cylinder-Final-03.png 967w\" sizes=\"(max-width: 351px) 100vw, 351px\" \/><\/span><\/p>\n<p>&nbsp;<\/p>\n<p>The area of the curved surface of the cylinder is equal to the area of the rectangular sheet.<\/p>\n<p>Therefore, the area of the curved surface = length of the rectangle x breadth of the rectangle.<\/p>\n<p>From this, we can infer that,<\/p>\n<p>Length of the rectangle = Circumference of the base of the cylinder<\/p>\n<p><span style=\"font-weight: 400;\">\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0= 2\u03c0r<\/span><\/p>\n<p><span style=\"font-weight: 400;\">Breadth of the rectangle = Height of the cylinder<\/span><\/p>\n<p><span style=\"font-weight: 400;\">\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0= h<\/span><\/p>\n<p><span style=\"font-weight: 400;\">Area of the curved surface = area of the rectangle\u00a0<\/span><\/p>\n<p><span style=\"font-weight: 400;\">\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 = length x breadth<\/span><\/p>\n<p><span style=\"font-weight: 400;\">\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0\u00a0= 2\u03c0rh<\/span><\/p>\n<p><span style=\"font-weight: 400;\">Hence, the\u00a0<\/span><b>Curved Surface Area of a Cylinder = 2\u03c0rh<\/b><\/p>\n<p>&nbsp;<\/p>\n<h2><b>Total Surface Area of a Cylinder<\/b><\/h2>\n<p><span style=\"font-weight: 400;\">Finding the total surface area of a cylinder includes calculating the sum of areas of all surfaces. As mentioned earlier, a cylinder has two types of surfaces, a curved and a circular; the sum of these two surface areas gives us the TSA of a cylinder.\u00a0<\/span><\/p>\n<p><span style=\"font-weight: 400;\"><\/span><\/p>\n<p><span style=\"font-weight: 400;\"><\/span><\/p>\n<h3><b>Total surface area of a cylinder formula<\/b><b><\/b><\/h3>\n<p>The total surface area of a cylinder is the sum of its lateral curved surface area and the area of two circular bases.<\/p>\n<p>TSA = CSA + area of circular bases<\/p>\n<p style=\"text-align: center;\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/eistudymaterial.s3.amazonaws.com\/CSA-of-Cylinder-Final-04-300x164.png\" width=\"351\" height=\"192\" alt=\"\" class=\"wp-image-4494 alignnone size-medium\" srcset=\"https:\/\/eistudymaterial.s3.amazonaws.com\/CSA-of-Cylinder-Final-04-300x164.png 300w, https:\/\/eistudymaterial.s3.amazonaws.com\/CSA-of-Cylinder-Final-04-768x420.png 768w, https:\/\/eistudymaterial.s3.amazonaws.com\/CSA-of-Cylinder-Final-04-480x262.png 480w, https:\/\/eistudymaterial.s3.amazonaws.com\/CSA-of-Cylinder-Final-04.png 957w\" sizes=\"(max-width: 351px) 100vw, 351px\" \/><\/p>\n<p><span style=\"font-weight: 400;\">Considering the height of a cylinder to be \u2018h\u2019 and radius as \u2018r\u2019, the total surface area will be:<\/span><\/p>\n<p><span style=\"font-weight: 400;\"><span class=\"katex-eq\" data-katex-display=\"false\">\\text { TSA }=2 \\pi r h+2 \\pi r^{2}<\/span><\/span><\/p>\n<p><span style=\"font-weight: 400;\">Hence, the\u00a0<\/span><b>Total Surface Area of a Cylinder = 2\u03c0r(h + r)<\/b><\/p>\n<p>&nbsp;<\/p>\n<h2><b>Solved Examples for calculating the Surface Area of a Cylinder<\/b><\/h2>\n<p><b><\/b><\/p>\n<p><b>Question 1<\/b><span style=\"font-weight: 400;\">: Ishan\u2019s parents are planning to renovate his room, and Ishan has demanded to decorate his play area with beautifully painted cylindrical tins. Calculate the cost of painting one cylindrical tin if the radius and height of the cylinder are 7 m and 15 m, respectively. The cost of painting the cylindrical containers is <span class=\"katex-eq\" data-katex-display=\"false\">\u20b9 2 \/ m^{2} <\/span><\/span><span style=\"font-weight: 400;\">.<br \/>(Take \u03c0=<span class=\"katex-eq\" data-katex-display=\"false\">\\frac{22}{7}<\/span>)<\/span><\/p>\n<p><span style=\"font-weight: 400;\"><\/span><\/p>\n<p><b>Solution<\/b><span style=\"font-weight: 400;\">:<\/span><\/p>\n<p><span style=\"font-weight: 400;\">Radius of cylindrical tin (r) = 7 m<\/span><\/p>\n<p><span style=\"font-weight: 400;\">Height of cylindrical tin (h) = 15 m<\/span><span style=\"font-weight: 400;\"><\/span><\/p>\n<p><span style=\"font-weight: 400;\">To find the area of painting, we need to find the total surface area of the cylinder.<\/span><\/p>\n<p><span style=\"font-weight: 400;\">Total surface area <\/span><\/p>\n<p><span style=\"font-weight: 400;\">=<span class=\"katex-eq\" data-katex-display=\"false\">2 \\pi r(h+r) m^{2}<\/span><\/span><\/p>\n<p><span style=\"font-weight: 400;\"><\/span><\/p>\n<p><span style=\"font-weight: 400;\"><span class=\"katex-eq\" data-katex-display=\"false\">=2 \\times \\frac{22}{7} \\times 7(15+7) \\mathrm{m}^{2} <\/span><\/span><\/p>\n<p><span style=\"font-weight: 400;\"><br \/><span class=\"katex-eq\" data-katex-display=\"false\">=2 \\times \\frac{22}{7} \\times 7 \\times 22 \\mathrm{~m}^{2} <\/span><\/span><\/p>\n<p><span style=\"font-weight: 400;\"><br \/><span class=\"katex-eq\" data-katex-display=\"false\">=968 \\mathrm{~m}^{2}<\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"font-weight: 400;\">Therefore, a total of <span class=\"katex-eq\" data-katex-display=\"false\">968 \\mathrm{~m}^{2}<\/span> <\/span><span style=\"font-weight: 400;\">of the area needs painting.<\/span><\/p>\n<p><span style=\"font-weight: 400;\">Calculating the cost of painting <span class=\"katex-eq\" data-katex-display=\"false\">968 \\mathrm{~m}^{2}<\/span><\/span><span style=\"font-weight: 400;\">\u00a0area of cylindrical tin at <span class=\"katex-eq\" data-katex-display=\"false\">\u20b9 2 \/ m^{2}<\/span><\/span><\/p>\n<p><span style=\"font-weight: 400;\">= \u20b9 968 x 2 <\/span><\/p>\n<p><span style=\"font-weight: 400;\">= \u20b91936<\/span><\/p>\n<p><span style=\"font-weight: 400;\">Hence, Ishan\u2019s parents will have to spend a total of \u20b91936 to paint one cylindrical tin to decorate his study area.<\/span><\/p>\n<p><span style=\"font-weight: 400;\"><\/span><\/p>\n<p><b>Question 2<\/b><span style=\"font-weight: 400;\">: Find the curved surface area of a cylinder whose diameter is 14 cm and height is 15 cm.<\/span><\/p>\n<p><b>Solution<\/b><span style=\"font-weight: 400;\">:<\/span><\/p>\n<p><span style=\"font-weight: 400;\">Radius of cylinder <span class=\"katex-eq\" data-katex-display=\"false\">(\\mathrm{r})=\\frac{14}{2} \\mathrm{~cm}=7 \\mathrm{~cm}<\/span><\/span><\/p>\n<p><span style=\"font-weight: 400;\">Height of cylinder (h) = 15 cm<\/span><\/p>\n<p><span style=\"font-weight: 400;\">CSA = 2\u03c0rh<\/span><\/p>\n<p><span style=\"font-weight: 400;\"><span class=\"katex-eq\" data-katex-display=\"false\">=2 \\times \\frac{22}{7} \\times 7 \\times 15 \\mathrm{~cm}^{2} <\/span><\/span><\/p>\n<p><span style=\"font-weight: 400;\"><span class=\"katex-eq\" data-katex-display=\"false\">=660 \\mathrm{~cm}^{2}<\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"font-weight: 400;\">Therefore, the curved surface area of a cylinder <span class=\"katex-eq\" data-katex-display=\"false\">=660 \\mathrm{~cm}^{2}<\/span>.<br \/><\/span><\/p>\n<p><span style=\"font-weight: 400;\"><\/span><\/p>\n<p>[\/et_pb_text][\/et_pb_column][et_pb_column type=&#8221;2_5&#8243; 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locked=&#8221;off&#8221; global_colors_info=&#8221;{}&#8221;]<\/p>\n<h1>Explore Other Topics<\/h1>\n<p>[\/et_pb_text][et_pb_text _builder_version=&#8221;4.10.7&#8243; _module_preset=&#8221;default&#8221; text_line_height=&#8221;2.2em&#8221; link_font_size=&#8221;16px&#8221; custom_margin=&#8221;||0px||false|false&#8221; custom_padding=&#8221;10px|15px|10px|28px|true|false&#8221; locked=&#8221;off&#8221; global_colors_info=&#8221;{}&#8221;]<\/p>\n<div>\n<div class=\"trr\"><a href=\"https:\/\/stgwebsite.mindspark.in\/wordpress\/math-concepts\/#geometry\" class=\"otherc\">Geometry<\/a><\/div>\n<div class=\"trr\"><a href=\"https:\/\/stgwebsite.mindspark.in\/wordpress\/math-concepts\/#trigonometry\" class=\"otherc\">Trigonometry<\/a><\/div>\n<div class=\"trr\"><a href=\"https:\/\/stgwebsite.mindspark.in\/wordpress\/math-concepts\/#operations\" class=\"otherc\">Operations<\/a><\/div>\n<div class=\"trr\"><a href=\"https:\/\/stgwebsite.mindspark.in\/wordpress\/math-concepts\/#numbers\" class=\"otherc\">Numbers<\/a><\/div>\n<\/div>\n<p>[\/et_pb_text][et_pb_text admin_label=&#8221;Related Concepts<br \/>\n&#8221; _builder_version=&#8221;4.9.11&#8243; _module_preset=&#8221;default&#8221; header_font=&#8221;|700|||||||&#8221; header_font_size=&#8221;25px&#8221; text_orientation=&#8221;center&#8221; custom_margin=&#8221;0px||0px||true|false&#8221; custom_padding=&#8221;8px|15px|0px|15px|false|true&#8221; locked=&#8221;off&#8221; global_colors_info=&#8221;{}&#8221;]<\/p>\n<h1>Related Concepts<\/h1>\n<p>[\/et_pb_text][et_pb_text _builder_version=&#8221;4.13.1&#8243; _module_preset=&#8221;default&#8221; text_line_height=&#8221;2.2em&#8221; link_font_size=&#8221;16px&#8221; custom_margin=&#8221;||0px||false|false&#8221; custom_padding=&#8221;10px|15px|10px|28px|true|false&#8221; locked=&#8221;off&#8221; global_colors_info=&#8221;{}&#8221;]<\/p>\n<div>\n<div class=\"trr\"><a href=\"https:\/\/mindspark.in\/studymaterial\/math-concepts\/surface-area-and-volume-formulas\/\" class=\"otherc\">Surface Area and Volume<\/a><\/div>\n<div class=\"trr\"><a href=\"https:\/\/mindspark.in\/studymaterial\/math-concepts\/lateral-surface-area-with-examples-and-faqs\/\" class=\"otherc\">Lateral Surface Area<\/a><\/div>\n<div class=\"trr\"><a href=\"https:\/\/mindspark.in\/studymaterial\/math-concepts\/area-of-hollow-cylinder-with-examples-and-faqs\/\" class=\"otherc\">Area of Hollow Cylinder<\/a><\/div>\n<\/div>\n<p>[\/et_pb_text][\/et_pb_column][\/et_pb_row][et_pb_row admin_label=&#8221;Row for space&#8221; 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_module_preset=&#8221;default&#8221; background_color=&#8221;#fff7d6&#8243; width=&#8221;100%&#8221; max_width=&#8221;1310px&#8221; height=&#8221;134px&#8221; custom_margin=&#8221;||50px||false|false&#8221; custom_padding=&#8221;12px||12px||true|false&#8221; border_radii=&#8221;on|11px|11px|11px|11px&#8221; locked=&#8221;off&#8221; collapsed=&#8221;off&#8221; global_colors_info=&#8221;{}&#8221;][et_pb_column type=&#8221;4_4&#8243; _builder_version=&#8221;4.9.10&#8243; _module_preset=&#8221;default&#8221; global_colors_info=&#8221;{}&#8221;][et_pb_image src=&#8221;https:\/\/stgwebsite.mindspark.in\/wordpress\/wp-content\/uploads\/2021\/08\/calloutImage.png&#8221; title_text=&#8221;calloutImage&#8221; show_bottom_space=&#8221;off&#8221; admin_label=&#8221;Image&#8221; module_class=&#8221;img1&#8243; _builder_version=&#8221;4.10.8&#8243; _module_preset=&#8221;default&#8221; width=&#8221;25px&#8221; height=&#8221;60px&#8221; custom_padding=&#8221;2px||2px||true|false&#8221; global_colors_info=&#8221;{}&#8221;][\/et_pb_image][et_pb_text module_class=&#8221;ftstyle&#8221; _builder_version=&#8221;4.9.10&#8243; _module_preset=&#8221;default&#8221; text_orientation=&#8221;center&#8221; global_colors_info=&#8221;{}&#8221;]<\/p>\n<div class=\"ffmanage\">\n<div class=\"textmanagestyle\">\n<div class=\"fone\">\n<p>Ready to get started ?<\/p>\n<\/div>\n<div class=\"sone\">\n<p class=\"ffbtn\"><a href=\"https:\/\/mindspark.in\/free-trial\">Start Free Trial<\/a><\/p>\n<\/div>\n<\/div>\n<\/div>\n<p>[\/et_pb_text][et_pb_image src=&#8221;https:\/\/stgwebsite.mindspark.in\/wordpress\/wp-content\/uploads\/2021\/08\/down-circle.png&#8221; title_text=&#8221;down-circle&#8221; show_bottom_space=&#8221;off&#8221; align=&#8221;right&#8221; module_class=&#8221;img2&#8243; _builder_version=&#8221;4.9.10&#8243; _module_preset=&#8221;default&#8221; width=&#8221;44px&#8221; height=&#8221;18px&#8221; custom_padding=&#8221;2px||2px||true|false&#8221; global_colors_info=&#8221;{}&#8221;][\/et_pb_image][\/et_pb_column][\/et_pb_row][et_pb_row admin_label=&#8221;FAQ Row&#8221; _builder_version=&#8221;4.9.11&#8243; _module_preset=&#8221;default&#8221; width=&#8221;100%&#8221; max_width=&#8221;1310px&#8221; custom_padding=&#8221;|40px||40px|false|true&#8221; global_colors_info=&#8221;{}&#8221;][et_pb_column type=&#8221;4_4&#8243; _builder_version=&#8221;4.9.11&#8243; _module_preset=&#8221;default&#8221; global_colors_info=&#8221;{}&#8221;][et_pb_text admin_label=&#8221;FAQ&#8221; module_class=&#8221;faqstyl&#8221; _builder_version=&#8221;4.13.1&#8243; _module_preset=&#8221;default&#8221; text_font_size=&#8221;16px&#8221; header_font=&#8221;|700|||||||&#8221; header_text_align=&#8221;center&#8221; header_line_height=&#8221;2.5em&#8221; background_color=&#8221;#dbedc6&#8243; max_width=&#8221;80%&#8221; module_alignment=&#8221;center&#8221; custom_margin=&#8221;||||false|false&#8221; custom_padding=&#8221;30px|25px|30px|25px|true|true&#8221; border_radii=&#8221;on|10px|10px|10px|10px&#8221; global_colors_info=&#8221;{}&#8221;]<\/p>\n<h1>Frequently Asked Questions<span style=\"font-weight: 400;\"><span style=\"font-weight: 400;\">\u00a0<\/span><\/span><\/h1>\n<ol><\/ol>\n<h3><strong>\u00a0Q1. What is a Cylinder?<\/strong><\/h3>\n<p><span style=\"font-weight: 400;\"><strong>Ans: <\/strong><\/span>A cylinder is a 3-D shape with a curved surface enclosed by two parallel circular bases at both ends.<\/p>\n<h3><strong>Q2. Is there any relation between the CSA and TSA of a cylinder?<\/strong><\/h3>\n<p><strong>Ans: <\/strong>The Total Surface Area of a cylinder is the sum of its Curved Surface Area and areas of two circular bases.<strong><\/strong><\/p>\n<h3><strong>Q3. What is a curved surface of a cylinder?<br \/><\/strong><\/h3>\n<p><strong>Ans: <\/strong>A curved surface refers to a surface that is rounded and not flat.<\/p>\n<p>[\/et_pb_text][\/et_pb_column][\/et_pb_row][\/et_pb_section]<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Meta Description: We can calculate the sum of the terms in a geometric progression using the formula  S = a(1-r^n)\/(1-r) when r < 1 and  S = a(r^n-1)\/(r-1)when r>1<\/p>\n","protected":false},"author":10,"featured_media":0,"parent":714,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"","meta":{"_et_pb_use_builder":"on","_et_pb_old_content":"","_et_gb_content_width":"","footnotes":""},"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v17.6 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>Curved Surface Area of Cylinder \u2013 Derivation, Formula and Examples - mydomain<\/title>\n<meta name=\"description\" content=\"Meta Description: We can calculate the sum of the terms in a geometric progression using the formula S = a(1-r^n)\/(1-r) when r &lt; 1 and S = a(r^n-1)\/(r-1)when r&gt;1\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/stgwebsite.mindspark.in\/studymaterial\/math-concepts\/curved-surface-area-of-cylinder-derivation-formula-and-examples\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Curved Surface Area of Cylinder \u2013 Derivation, Formula and Examples - 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