{"id":5807,"date":"2021-12-14T19:30:20","date_gmt":"2021-12-14T19:30:20","guid":{"rendered":"https:\/\/stgwebsite.mindspark.in\/studymaterial\/?page_id=5807"},"modified":"2022-01-02T13:35:08","modified_gmt":"2022-01-02T13:35:08","slug":"surface-area-of-cone-formula-derivation-examples","status":"publish","type":"page","link":"https:\/\/stgwebsite.mindspark.in\/studymaterial\/math-concepts\/surface-area-of-cone-formula-derivation-examples\/","title":{"rendered":"Surface Area of Cone \u2013 Formula, Derivation, Examples"},"content":{"rendered":"<p>[et_pb_section fb_built=&#8221;1&#8243; admin_label=&#8221;Section&#8221; module_class=&#8221;mainsec&#8221; _builder_version=&#8221;4.10.4&#8243; _module_preset=&#8221;default&#8221; background_color=&#8221;#e0f2fd&#8221; z_index=&#8221;1&#8243; custom_padding=&#8221;5px||5px||true|false&#8221; locked=&#8221;off&#8221; collapsed=&#8221;off&#8221; global_colors_info=&#8221;{}&#8221;][et_pb_row column_structure=&#8221;3_5,2_5&#8243; custom_padding_last_edited=&#8221;on|phone&#8221; _builder_version=&#8221;4.10.8&#8243; _module_preset=&#8221;default&#8221; background_color=&#8221;#FFFFFF&#8221; width=&#8221;100%&#8221; max_width=&#8221;1310px&#8221; custom_padding=&#8221;|51px|40px|51px|false|true&#8221; custom_padding_tablet=&#8221;&#8221; custom_padding_phone=&#8221;|40px|30px|40px|false|true&#8221; border_radii=&#8221;on|10px|10px|10px|10px&#8221; global_colors_info=&#8221;{}&#8221;][et_pb_column type=&#8221;3_5&#8243; admin_label=&#8221;Column L&#8221; _builder_version=&#8221;4.9.10&#8243; _module_preset=&#8221;default&#8221; global_colors_info=&#8221;{}&#8221;][et_pb_text admin_label=&#8221;Acute Angles<br \/>\n&#8221; _builder_version=&#8221;4.11.3&#8243; _module_preset=&#8221;default&#8221; header_font=&#8221;|700|||||||&#8221; header_text_align=&#8221;left&#8221; header_font_size=&#8221;50px&#8221; header_line_height=&#8221;1.18em&#8221; custom_padding=&#8221;|0px||4px|false|false&#8221; header_font_size_tablet=&#8221;&#8221; header_font_size_phone=&#8221;35px&#8221; header_font_size_last_edited=&#8221;on|phone&#8221; global_colors_info=&#8221;{}&#8221;]<\/p>\n<h1>Surface Area of Cone \u2013 Formula, Derivation, Examples<\/h1>\n<p>[\/et_pb_text][et_pb_text admin_label=&#8221;Text&#8221; _builder_version=&#8221;4.13.1&#8243; _module_preset=&#8221;default&#8221; text_font_size=&#8221;16px&#8221; header_2_font=&#8221;|600|||||||&#8221; header_2_text_color=&#8221;#a01414&#8243; header_3_font=&#8221;|600|||||||&#8221; custom_padding=&#8221;15px|15px|54px|4px|false|false&#8221; global_colors_info=&#8221;{}&#8221;]<\/p>\n<h2><strong>What is a cone?<\/strong><\/h2>\n<p><span style=\"font-weight: 400;\">We&#8217;re sure you might&#8217;ve seen birthday caps and ice cream cones; these are 3-D structures having a circular base and a pointed end (apex). This shape is known as a cone. Since the base is circular, it is evident that it has a radius (r) and a diameter. The axis connecting the centre of the circular base to the cone&#8217;s apex is known as the height (h) of the cone. Thus, a cone has three parts \u2013 radius, height and slant height.\u00a0<\/span><\/p>\n<p><span style=\"font-weight: 400;\"><\/span><\/p>\n<p style=\"text-align: center;\"><span style=\"font-weight: 400;\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/eistudymaterial.s3.amazonaws.com\/surface-area-of-cone_commented-01-216x300.png\" width=\"301\" height=\"418\" alt=\"\" class=\"wp-image-5809 alignnone size-medium\" srcset=\"https:\/\/eistudymaterial.s3.amazonaws.com\/surface-area-of-cone_commented-01-216x300.png 216w, https:\/\/eistudymaterial.s3.amazonaws.com\/surface-area-of-cone_commented-01.png 230w\" sizes=\"(max-width: 301px) 100vw, 301px\" \/><\/span><\/p>\n<p><span style=\"font-weight: 400;\"><\/span><\/p>\n<p><span style=\"font-weight: 400;\">A cone is of two types \u2013 a right circular cone and an oblique cone. In this article, we will make you more aware of a right circular cone.<\/span><\/p>\n<p>&nbsp;<\/p>\n<h2><strong>Right circular cone<\/strong><\/h2>\n<p><span style=\"font-weight: 400;\">A cone with an axis running perpendicular to the <\/span><span style=\"font-weight: 400;\">base is called a right circular cone. In this article we will only talk about a right circular cone. The length of the apex and any point on the circumference of the cone is called its slant height (l). All right circular cones are cones, but all cones might not be right circular in nature.<\/span><\/p>\n<p><span style=\"font-weight: 400;\">In right circular cones, the radius, height and slant height make a right angled triangle. It means that if we don&#8217;t have the value of slant height in the question but have radius and height \u2013 we can still calculate the slant height and then calculate the CSA and TSA.<\/span><span style=\"font-weight: 400;\"><\/span><\/p>\n<p><span style=\"font-weight: 400;\"><\/span><\/p>\n<h2><strong>The surface area of a cone<\/strong><\/h2>\n<p><span style=\"font-weight: 400;\">The measure of a cone&#8217;s surface area is the area occupied by a cone&#8217;s surface. Now, we must see that a cone has two kinds of surface areas:<\/span><\/p>\n<ul>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-weight: 400;\">Curved surface area<\/span><\/li>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-weight: 400;\">Total surface area.\u00a0<\/span><\/li>\n<\/ul>\n<p><span style=\"font-weight: 400;\">The main <\/span><b>difference between the curved surface area and the total surface area<\/b><span style=\"font-weight: 400;\"> (TSA) of a cone is that the TSA consists of the <\/span><b>lateral surface area of the cone <\/b><span style=\"font-weight: 400;\">and the area of the circular base. In contrast, CSA consists of the area of the curved surface, excluding the flat surface.\u00a0<\/span><\/p>\n<p><span style=\"font-weight: 400;\"><\/span><\/p>\n<h2><strong>The surface area of a cone formula<\/strong><\/h2>\n<p><span style=\"font-weight: 400;\">You can calculate the\u00a0 <\/span><b>CSA and TSA of a cone<\/b><span style=\"font-weight: 400;\">, by finding the area of the cone&#8217;s base and the <\/span><b>curved surface area of the cone<\/b><span style=\"font-weight: 400;\">.<\/span><\/p>\n<h3><span style=\"font-weight: 400;\"><\/span><\/h3>\n<h3><strong>The curved surface area of a cone<\/strong><\/h3>\n<p><span style=\"font-weight: 400;\">You can look at the curved surface of a cone as a triangle. For this, you can slice up the curved surface into thin pieces to approximate them as small triangles. The total base length of these triangles is equal to the circumference of the cone&#8217;s circular base<\/span><span style=\"font-weight: 400;\">,<\/span><span style=\"font-weight: 400;\"> and the slant height of the cone is now the height of each triangle.<\/span><\/p>\n<p><span style=\"font-weight: 400;\">The sum of bases of all triangles = circumference of the base of the cone = 2\u03c0r<\/span><\/p>\n<p><span style=\"font-weight: 400;\">Height of each triangle = slant height of the cone = <span class=\"katex-eq\" data-katex-display=\"false\">l<\/span><\/span><\/p>\n<p><span style=\"font-weight: 400;\"><\/span><\/p>\n<p><span style=\"font-weight: 400;\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/eistudymaterial.s3.amazonaws.com\/surface-area-of-cone_commented-02-300x105.png\" width=\"506\" height=\"177\" alt=\"\" class=\"wp-image-5811 alignnone size-medium\" style=\"display: block; margin-left: auto; margin-right: auto;\" srcset=\"https:\/\/eistudymaterial.s3.amazonaws.com\/surface-area-of-cone_commented-02-300x105.png 300w, https:\/\/eistudymaterial.s3.amazonaws.com\/surface-area-of-cone_commented-02-480x168.png 480w, https:\/\/eistudymaterial.s3.amazonaws.com\/surface-area-of-cone_commented-02.png 714w\" sizes=\"(max-width: 506px) 100vw, 506px\" \/><\/span><\/p>\n<p><span style=\"font-weight: 400;\"><\/span><\/p>\n<p><span style=\"font-weight: 400;\">Let us consider the bases of the small triangles to be<\/span><\/p>\n<p><span style=\"font-weight: 400;\"><span class=\"katex-eq\" data-katex-display=\"false\">b_1,b_2,b_3,<\/span> &#8230;.. respectively.<\/span><\/p>\n<p><span style=\"font-weight: 400;\">The heights of all the triangles are equal (<span class=\"katex-eq\" data-katex-display=\"false\">l<\/span>).\u00a0<\/span><\/p>\n<p><span style=\"font-weight: 400;\">The total area of these triangles will be the curved surface area.<\/span><\/p>\n<p><span style=\"font-weight: 400;\">Therefore the CSA = <span class=\"katex-eq\" data-katex-display=\"false\">(1\/2 \\times b_1 \\times l) + (1\/2 \\times b_2 \\times l) + .......<\/span>\u00a0<\/span><\/p>\n<p><span style=\"font-weight: 400;\">\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 = <span class=\"katex-eq\" data-katex-display=\"false\">(1\/2 \\times l)\u00a0 (b_1+ b_2 +b_3+.....)<\/span><\/span><\/p>\n<p><span style=\"font-weight: 400;\">\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 = <span class=\"katex-eq\" data-katex-display=\"false\">(1\/2 \\times l) \\times (2\\pi r)<\/span><\/span><\/p>\n<p><span style=\"font-weight: 400;\">\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 = <span class=\"katex-eq\" data-katex-display=\"false\">\\pi rl<\/span><\/span><\/p>\n<p><span style=\"font-weight: 400;\">Therefore, the <\/span><b>curved surface area of cone = <span style=\"font-weight: 400;\"><span class=\"katex-eq\" data-katex-display=\"false\">\\pi rl<\/span><\/span><\/b><\/p>\n<p><b><\/b><\/p>\n<h3><span style=\"font-weight: 400;\"><strong>The<\/strong> <\/span><b>total surface area of a cone<\/b><\/h3>\n<p><span style=\"font-weight: 400;\">The<\/span><b> total surface area of a cone<\/b><span style=\"font-weight: 400;\"> = area of circular base + CSA of cone<\/span><\/p>\n<p><span style=\"font-weight: 400;\">We know that the area of circular base <span class=\"katex-eq\" data-katex-display=\"false\">=\\pi r^{2}<\/span><\/span><\/p>\n<p><span style=\"font-weight: 400;\">And, CSA of cone = <span class=\"katex-eq\" data-katex-display=\"false\">\\pi rl<\/span><\/span><\/p>\n<p><span style=\"font-weight: 400;\">So, the total surface area of a cone <span class=\"katex-eq\" data-katex-display=\"false\">=\\pi r^{2}<\/span><\/span><span style=\"font-weight: 400;\">+ <span class=\"katex-eq\" data-katex-display=\"false\">\\pi rl<\/span><\/span><\/p>\n<p><span style=\"font-weight: 400;\">Therefore, the<\/span> total surface area of a cone =<b>\u00a0<span style=\"font-weight: 400;\"><span class=\"katex-eq\" data-katex-display=\"false\">\\pi r(r+l)<\/span><\/span><\/b><\/p>\n<p><span style=\"font-weight: 400;\">Also, the slant height of the cone <span class=\"katex-eq\" data-katex-display=\"false\">(l)=\\sqrt{\\left(r^{2}+h^{2}\\right)}<\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<h2><strong>Solved examples<\/strong><\/h2>\n<p><strong><\/strong><\/p>\n<p><b>Example 1:<\/b><span style=\"font-weight: 400;\">\u00a0<\/span><\/p>\n<p><span style=\"font-weight: 400;\">The radius and height of a right circular cone is 4 cm and 16 cm, respectively. What will the <\/span><b>total surface area of the cone be?<\/b><\/p>\n<p><b>Solution\u00a0<\/b><\/p>\n<p><span style=\"font-weight: 400;\">Given, radius (r) = 4 cm<\/span><\/p>\n<p><span style=\"font-weight: 400;\">Height of the cone (h) = 16 cm<\/span><\/p>\n<p><span style=\"font-weight: 400;\">Slant height of the cone <span class=\"katex-eq\" data-katex-display=\"false\">(l)=\\sqrt{\\left(r^{2}+h^{2}\\right)}<\/span><\/span><\/p>\n<p><span style=\"font-weight: 400;\">\u21d2 <span class=\"katex-eq\" data-katex-display=\"false\">l=\\sqrt{\\left(16^{2}+4^{2}\\right)}<\/span><\/span><\/p>\n<p><span style=\"font-weight: 400;\">\u21d2 <span class=\"katex-eq\" data-katex-display=\"false\">l=\\sqrt{256+16}<\/span><\/span><\/p>\n<p><span style=\"font-weight: 400;\">\u21d2 <span class=\"katex-eq\" data-katex-display=\"false\">l=\\sqrt{272}<\/span><\/span><\/p>\n<p><span style=\"font-weight: 400;\">\u2234 <span class=\"katex-eq\" data-katex-display=\"false\">l=16.49<\/span> cm<\/span><\/p>\n<p><span style=\"font-weight: 400;\">TSA of the cone <\/span><\/p>\n<p><span style=\"font-weight: 400;\">= <\/span><span style=\"font-weight: 400;\"><span class=\"katex-eq\" data-katex-display=\"false\">\\pi r(r+l)<\/span><\/span><\/p>\n<p><span style=\"font-weight: 400;\">= 3.14 x 4 (4 + 16)<\/span><\/p>\n<p><span style=\"font-weight: 400;\">= 3.14 x 80<\/span><\/p>\n<p><span style=\"font-weight: 400;\">= 251.2 cm\u00b2<\/span><\/p>\n<p><span style=\"font-weight: 400;\">Therefore, the <\/span><span style=\"font-weight: 400;\">TSA of the cone is 251.2 cm\u00b2 .<\/span><\/p>\n<p><span style=\"font-weight: 400;\"><\/span><\/p>\n<p><b>Example 2:<\/b><\/p>\n<p><span style=\"font-weight: 400;\">The slant height of a cone is 24 cm, and the radius is 10 cm. Find <\/span><b>the lateral surface area of the cone<\/b><span style=\"font-weight: 400;\">?<\/span><\/p>\n<p><b>Solution:<\/b><\/p>\n<p><span style=\"font-weight: 400;\">Given,\u00a0<\/span><\/p>\n<p><span style=\"font-weight: 400;\">Radius (r) = 10 cm<\/span><\/p>\n<p><span style=\"font-weight: 400;\">Slant height (l) = 24 cm<\/span><\/p>\n<p><span style=\"font-weight: 400;\">Putting these values in the formula, <\/span><b>CSA of cone<\/b><span style=\"font-weight: 400;\"> <\/span><\/p>\n<p><span style=\"font-weight: 400;\">= <span class=\"katex-eq\" data-katex-display=\"false\">\\pi rl<\/span><\/span><\/p>\n<p><span style=\"font-weight: 400;\"><span class=\"katex-eq\" data-katex-display=\"false\">=3.14 \\times 10 \\times 24 \\mathrm{~cm}^{2} <\/span><br \/><\/span><\/p>\n<p><span style=\"font-weight: 400;\"><span class=\"katex-eq\" data-katex-display=\"false\">\n=753.6 \\mathrm{~cm}^{2}<\/span><\/span><\/p>\n<p><span style=\"font-weight: 400;\">Therefore, the CSA of the cone is <\/span><span style=\"font-weight: 400;\"><span class=\"katex-eq\" data-katex-display=\"false\"> =753.6 \\mathrm{~cm}^{2}<\/span>.<\/span><\/p>\n<p>[\/et_pb_text][\/et_pb_column][et_pb_column type=&#8221;2_5&#8243; module_id=&#8221;stickysideR&#8221; admin_label=&#8221;Column R&#8221; _builder_version=&#8221;4.10.4&#8243; _module_preset=&#8221;default&#8221; background_color=&#8221;#fdefe0&#8243; custom_padding=&#8221;25px|25px|25px|25px|true|true&#8221; sticky_position=&#8221;top&#8221; sticky_offset_top=&#8221;-280px&#8221; sticky_limit_top=&#8221;row&#8221; sticky_limit_bottom=&#8221;row&#8221; sticky_position_tablet=&#8221;none&#8221; sticky_position_phone=&#8221;none&#8221; sticky_position_last_edited=&#8221;on|desktop&#8221; sticky_limit_bottom_tablet=&#8221;&#8221; sticky_limit_bottom_phone=&#8221;&#8221; sticky_limit_bottom_last_edited=&#8221;on|phone&#8221; border_radii=&#8221;on|15px|15px|15px|15px&#8221; box_shadow_style=&#8221;preset3&#8243; global_colors_info=&#8221;{}&#8221;][et_pb_image src=&#8221;https:\/\/eistudymaterial.s3.amazonaws.com\/1080&#215;1080.png&#8221; alt=&#8221;Free Trial banner&#8221; title_text=&#8221;Mindspark Free Trial Banner&#8221; url=&#8221;https:\/\/mindspark.in\/free-trial&#8221; 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locked=&#8221;off&#8221; global_colors_info=&#8221;{}&#8221;]<\/p>\n<h1>Explore Other Topics<\/h1>\n<p>[\/et_pb_text][et_pb_text _builder_version=&#8221;4.10.7&#8243; _module_preset=&#8221;default&#8221; text_line_height=&#8221;2.2em&#8221; link_font_size=&#8221;16px&#8221; custom_margin=&#8221;||0px||false|false&#8221; custom_padding=&#8221;10px|15px|10px|28px|true|false&#8221; locked=&#8221;off&#8221; global_colors_info=&#8221;{}&#8221;]<\/p>\n<div>\n<div class=\"trr\"><a href=\"https:\/\/stgwebsite.mindspark.in\/wordpress\/math-concepts\/#geometry\" class=\"otherc\">Geometry<\/a><\/div>\n<div class=\"trr\"><a href=\"https:\/\/stgwebsite.mindspark.in\/wordpress\/math-concepts\/#trigonometry\" class=\"otherc\">Trigonometry<\/a><\/div>\n<div class=\"trr\"><a href=\"https:\/\/stgwebsite.mindspark.in\/wordpress\/math-concepts\/#operations\" class=\"otherc\">Operations<\/a><\/div>\n<div class=\"trr\"><a href=\"https:\/\/stgwebsite.mindspark.in\/wordpress\/math-concepts\/#numbers\" class=\"otherc\">Numbers<\/a><\/div>\n<\/div>\n<p>[\/et_pb_text][et_pb_text admin_label=&#8221;Related Concepts<br \/>\n&#8221; _builder_version=&#8221;4.9.11&#8243; _module_preset=&#8221;default&#8221; header_font=&#8221;|700|||||||&#8221; header_font_size=&#8221;25px&#8221; text_orientation=&#8221;center&#8221; custom_margin=&#8221;0px||0px||true|false&#8221; custom_padding=&#8221;8px|15px|0px|15px|false|true&#8221; locked=&#8221;off&#8221; global_colors_info=&#8221;{}&#8221;]<\/p>\n<h1>Related Concepts<\/h1>\n<p>[\/et_pb_text][et_pb_text _builder_version=&#8221;4.13.1&#8243; _module_preset=&#8221;default&#8221; text_line_height=&#8221;2.2em&#8221; link_font_size=&#8221;16px&#8221; custom_margin=&#8221;||0px||false|false&#8221; custom_padding=&#8221;10px|15px|10px|28px|true|false&#8221; locked=&#8221;off&#8221; global_colors_info=&#8221;{}&#8221;]<\/p>\n<div class=\"trr\"><a href=\"https:\/\/mindspark.in\/studymaterial\/math-concepts\/surface-area-and-volume-formulas\/\" class=\"otherc\">Surface Area and Volume Formula<\/a><\/div>\n<div class=\"trr\"><a href=\"https:\/\/mindspark.in\/studymaterial\/math-concepts\/volume-of-right-circular-cone-meaning-formula-2\/\" class=\"otherc\">Volume of Right Circular Cone<\/a><\/div>\n<div class=\"trr\"><a href=\"https:\/\/mindspark.in\/studymaterial\/math-concepts\/lateral-surface-area-with-examples-and-faqs\/\" class=\"otherc\">Lateral Surface Area<\/a><\/div>\n<p>[\/et_pb_text][\/et_pb_column][\/et_pb_row][et_pb_row admin_label=&#8221;Row for space&#8221; _builder_version=&#8221;4.10.6&#8243; _module_preset=&#8221;default&#8221; locked=&#8221;off&#8221; global_colors_info=&#8221;{}&#8221;][et_pb_column type=&#8221;4_4&#8243; _builder_version=&#8221;4.9.11&#8243; _module_preset=&#8221;default&#8221; global_colors_info=&#8221;{}&#8221;][et_pb_divider show_divider=&#8221;off&#8221; _builder_version=&#8221;4.10.4&#8243; _module_preset=&#8221;default&#8221; global_colors_info=&#8221;{}&#8221;][\/et_pb_divider][\/et_pb_column][\/et_pb_row][\/et_pb_section][et_pb_section fb_built=&#8221;1&#8243; admin_label=&#8221;banner and faq Section&#8221; module_class=&#8221;mainsec2&#8243; _builder_version=&#8221;4.10.4&#8243; _module_preset=&#8221;default&#8221; custom_padding=&#8221;40px||0px||false|false&#8221; global_colors_info=&#8221;{}&#8221;][et_pb_row use_custom_gutter=&#8221;on&#8221; gutter_width=&#8221;1&#8243; make_equal=&#8221;on&#8221; disabled_on=&#8221;on|on|off&#8221; admin_label=&#8221;banner Row&#8221; _builder_version=&#8221;4.10.4&#8243; _module_preset=&#8221;default&#8221; background_color=&#8221;#fff7d6&#8243; width=&#8221;100%&#8221; max_width=&#8221;1310px&#8221; height=&#8221;134px&#8221; custom_margin=&#8221;||50px||false|false&#8221; custom_padding=&#8221;12px||12px||true|false&#8221; border_radii=&#8221;on|11px|11px|11px|11px&#8221; locked=&#8221;off&#8221; collapsed=&#8221;off&#8221; global_colors_info=&#8221;{}&#8221;][et_pb_column type=&#8221;4_4&#8243; _builder_version=&#8221;4.9.10&#8243; _module_preset=&#8221;default&#8221; global_colors_info=&#8221;{}&#8221;][et_pb_image src=&#8221;https:\/\/stgwebsite.mindspark.in\/wordpress\/wp-content\/uploads\/2021\/08\/calloutImage.png&#8221; title_text=&#8221;calloutImage&#8221; show_bottom_space=&#8221;off&#8221; admin_label=&#8221;Image&#8221; module_class=&#8221;img1&#8243; _builder_version=&#8221;4.10.8&#8243; _module_preset=&#8221;default&#8221; width=&#8221;25px&#8221; height=&#8221;60px&#8221; custom_padding=&#8221;2px||2px||true|false&#8221; global_colors_info=&#8221;{}&#8221;][\/et_pb_image][et_pb_text module_class=&#8221;ftstyle&#8221; _builder_version=&#8221;4.9.10&#8243; _module_preset=&#8221;default&#8221; text_orientation=&#8221;center&#8221; global_colors_info=&#8221;{}&#8221;]<\/p>\n<div class=\"ffmanage\">\n<div class=\"textmanagestyle\">\n<div class=\"fone\">\n<p>Ready to get started ?<\/p>\n<\/div>\n<div class=\"sone\">\n<p class=\"ffbtn\"><a href=\"https:\/\/mindspark.in\/free-trial\">Start Free Trial<\/a><\/p>\n<\/div>\n<\/div>\n<\/div>\n<p>[\/et_pb_text][et_pb_image src=&#8221;https:\/\/stgwebsite.mindspark.in\/wordpress\/wp-content\/uploads\/2021\/08\/down-circle.png&#8221; title_text=&#8221;down-circle&#8221; show_bottom_space=&#8221;off&#8221; align=&#8221;right&#8221; module_class=&#8221;img2&#8243; _builder_version=&#8221;4.9.10&#8243; _module_preset=&#8221;default&#8221; width=&#8221;44px&#8221; height=&#8221;18px&#8221; custom_padding=&#8221;2px||2px||true|false&#8221; global_colors_info=&#8221;{}&#8221;][\/et_pb_image][\/et_pb_column][\/et_pb_row][et_pb_row admin_label=&#8221;FAQ Row&#8221; _builder_version=&#8221;4.9.11&#8243; _module_preset=&#8221;default&#8221; width=&#8221;100%&#8221; max_width=&#8221;1310px&#8221; custom_padding=&#8221;|40px||40px|false|true&#8221; global_colors_info=&#8221;{}&#8221;][et_pb_column type=&#8221;4_4&#8243; _builder_version=&#8221;4.9.11&#8243; _module_preset=&#8221;default&#8221; global_colors_info=&#8221;{}&#8221;][et_pb_text admin_label=&#8221;FAQ&#8221; module_class=&#8221;faqstyl&#8221; _builder_version=&#8221;4.13.1&#8243; _module_preset=&#8221;default&#8221; text_font_size=&#8221;16px&#8221; header_font=&#8221;|700|||||||&#8221; header_text_align=&#8221;center&#8221; header_line_height=&#8221;2.5em&#8221; background_color=&#8221;#dbedc6&#8243; max_width=&#8221;80%&#8221; module_alignment=&#8221;center&#8221; custom_margin=&#8221;||||false|false&#8221; custom_padding=&#8221;30px|25px|30px|25px|true|true&#8221; border_radii=&#8221;on|10px|10px|10px|10px&#8221; global_colors_info=&#8221;{}&#8221;]<\/p>\n<h1>Frequently Asked Questions<span style=\"font-weight: 400;\"><span style=\"font-weight: 400;\">\u00a0<\/span><\/span><\/h1>\n<ol><\/ol>\n<h3><strong>Q1. What is a right circular cone?<br \/><\/strong><\/h3>\n<p><span style=\"font-weight: 400;\"><strong>Ans: <\/strong><\/span><span style=\"font-weight: 400;\">It is a cone where an axis of the cone joining the apex and the centre of the circular base falls perpendicularly on the base.\u00a0 In this article, all along we were talking about the right circular cone only.\u00a0<\/span><span style=\"font-weight: 400;\"><strong><\/strong><strong><\/strong><\/span><span style=\"font-weight: 400;\"><\/span><span style=\"font-weight: 400;\"><\/span><\/p>\n<h3><strong>Q2. What is the formula of the CSA and TSA of a cone?<br \/><\/strong><\/h3>\n<p><strong>Ans: <\/strong><span style=\"font-weight: 400;\">The TSA of a cone is <span class=\"katex-eq\" data-katex-display=\"false\">\\pi r(r+l)<\/span>, whereas the <\/span><b>CSA of a cone <\/b><span style=\"font-weight: 400;\">is <span class=\"katex-eq\" data-katex-display=\"false\">\\pi rl<\/span>.<\/span><span style=\"font-weight: 400;\"><\/span><\/p>\n<h3><strong>Q3. What is the formula to find the slant height of a right circular cone?<\/strong><\/h3>\n<p><strong>Ans: <\/strong><span style=\"font-weight: 400;\">The <\/span><b>slant height of a right circular cone formula<\/b><span style=\"font-weight: 400;\"> is <span class=\"katex-eq\" data-katex-display=\"false\">l=\\sqrt{{\\text{r}}^2+{\\text{h}}^2}<\/span><\/span><span style=\"font-weight: 400;\">, where r and h are the radius and height of the cone, respectively.<\/span><strong><\/strong><strong><br \/><\/strong><\/p>\n<p>[\/et_pb_text][\/et_pb_column][\/et_pb_row][\/et_pb_section]<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Meta Description: We can calculate the sum of the terms in a geometric progression using the formula  S = a(1-r^n)\/(1-r) when r < 1 and  S = a(r^n-1)\/(r-1)when r>1<\/p>\n","protected":false},"author":10,"featured_media":0,"parent":714,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"","meta":{"_et_pb_use_builder":"on","_et_pb_old_content":"","_et_gb_content_width":"","footnotes":""},"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v17.6 - 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