{"id":5963,"date":"2021-12-16T03:41:02","date_gmt":"2021-12-16T03:41:02","guid":{"rendered":"https:\/\/stgwebsite.mindspark.in\/studymaterial\/?page_id=5963"},"modified":"2022-01-03T08:07:02","modified_gmt":"2022-01-03T08:07:02","slug":"what-is-a-perpendicular-bisector","status":"publish","type":"page","link":"https:\/\/stgwebsite.mindspark.in\/studymaterial\/math-concepts\/what-is-a-perpendicular-bisector\/","title":{"rendered":"WHAT IS A PERPENDICULAR BISECTOR"},"content":{"rendered":"<p>[et_pb_section fb_built=&#8221;1&#8243; admin_label=&#8221;Section&#8221; module_class=&#8221;mainsec&#8221; _builder_version=&#8221;4.10.4&#8243; _module_preset=&#8221;default&#8221; background_color=&#8221;#e0f2fd&#8221; z_index=&#8221;1&#8243; custom_padding=&#8221;5px||5px||true|false&#8221; locked=&#8221;off&#8221; collapsed=&#8221;off&#8221; global_colors_info=&#8221;{}&#8221;][et_pb_row column_structure=&#8221;3_5,2_5&#8243; custom_padding_last_edited=&#8221;on|phone&#8221; _builder_version=&#8221;4.10.8&#8243; _module_preset=&#8221;default&#8221; background_color=&#8221;#FFFFFF&#8221; width=&#8221;100%&#8221; max_width=&#8221;1310px&#8221; custom_padding=&#8221;|51px|40px|51px|false|true&#8221; custom_padding_tablet=&#8221;&#8221; custom_padding_phone=&#8221;|40px|30px|40px|false|true&#8221; border_radii=&#8221;on|10px|10px|10px|10px&#8221; global_colors_info=&#8221;{}&#8221;][et_pb_column type=&#8221;3_5&#8243; admin_label=&#8221;Column L&#8221; _builder_version=&#8221;4.9.10&#8243; _module_preset=&#8221;default&#8221; global_colors_info=&#8221;{}&#8221;][et_pb_text admin_label=&#8221;Acute Angles<br \/>\n&#8221; _builder_version=&#8221;4.11.3&#8243; _module_preset=&#8221;default&#8221; header_font=&#8221;|700|||||||&#8221; header_text_align=&#8221;left&#8221; header_font_size=&#8221;50px&#8221; header_line_height=&#8221;1.18em&#8221; custom_padding=&#8221;|0px||4px|false|false&#8221; header_font_size_tablet=&#8221;&#8221; header_font_size_phone=&#8221;35px&#8221; header_font_size_last_edited=&#8221;on|phone&#8221; global_colors_info=&#8221;{}&#8221;]<\/p>\n<h1>WHAT IS A PERPENDICULAR BISECTOR<\/h1>\n<p>[\/et_pb_text][et_pb_text admin_label=&#8221;Text&#8221; _builder_version=&#8221;4.13.1&#8243; _module_preset=&#8221;default&#8221; text_font_size=&#8221;16px&#8221; header_2_font=&#8221;|600|||||||&#8221; header_2_text_color=&#8221;#a01414&#8243; header_3_font=&#8221;|600|||||||&#8221; custom_padding=&#8221;15px|15px|54px|4px|false|false&#8221; global_colors_info=&#8221;{}&#8221;]<\/p>\n<h2><b>PERPENDICULAR BISECTOR<\/b><\/h2>\n<p><span style=\"font-weight: 400;\">A perpendicular bisector is a line that divides a given line segment into equal parts and forms 90\u00b0 angles at the intersection points. The term bisect itself means dividing equally. Bisectors intersect the line segment and form angles of 90 degrees on it.\u00a0<\/span><\/p>\n<p><span style=\"font-weight: 400;\">It is very easy to construct a perpendicular bisector using a ruler and compass.<\/span><\/p>\n<p><span style=\"font-weight: 400;\"><\/span><\/p>\n<p><b>PROPERTIES OF A PERPENDICULAR BISECTOR<\/b><\/p>\n<p><b><\/b><\/p>\n<ol>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-weight: 400;\">Perpendicular bisectors divide the segment into equal parts so any point that is on the perpendicular bisector is equidistant from both the ends of the segment.<br \/><\/span><span style=\"font-weight: 400;\"><\/span><span style=\"font-weight: 400;\"><br \/><\/span><\/li>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-weight: 400;\">There can only be one perpendicular bisector for a given line segment.<br \/><\/span><span style=\"font-weight: 400;\"><\/span><span style=\"font-weight: 400;\"><br \/><\/span><\/li>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-weight: 400;\">A perpendicular bisector makes an angle of 90 degrees with the line that it bisects.<br \/><\/span><span style=\"font-weight: 400;\"><\/span><span style=\"font-weight: 400;\"><\/span><span style=\"font-weight: 400;\"><br \/><\/span><\/li>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-weight: 400;\">When we draw the three perpendicular bisectors of a triangle, the meeting point is called the circumcentre. It is different for different types of triangles. The circumcentre is inside the triangle in case of an acute triangle, outside of the triangle in case of an obtuse triangle and at the hypotenuse in case of right-angled triangles.<\/span><\/li>\n<\/ol>\n<p><span style=\"font-weight: 400;\"><\/span><\/p>\n<p><b>HOW TO CONSTRUCT A PERPENDICULAR BISECTOR FOR A LINE SEGMENT<\/b><\/p>\n<p><span style=\"font-weight: 400;\">Let us learn how to construct a perpendicular bisector of a line segment.<\/span><\/p>\n<p><span style=\"font-weight: 400;\"><\/span><\/p>\n<p style=\"text-align: center;\"><span style=\"font-weight: 400;\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/eistudymaterial.s3.amazonaws.com\/ap-283x300.jpg\" width=\"352\" height=\"373\" alt=\"\" class=\"wp-image-5966 alignnone size-medium\" srcset=\"https:\/\/eistudymaterial.s3.amazonaws.com\/ap-283x300.jpg 283w, https:\/\/eistudymaterial.s3.amazonaws.com\/ap.jpg 439w\" sizes=\"(max-width: 352px) 100vw, 352px\" \/><\/span><\/p>\n<p><span style=\"font-weight: 400;\"><\/span><\/p>\n<p><span style=\"font-weight: 400;\"><strong>Step 1:<\/strong>\u00a0Draw a line segment PQ of any length.<\/span><\/p>\n<p><span style=\"font-weight: 400;\"><strong>Step 2:<\/strong>\u00a0Place the compass at point P taking it as a centre and more than half of the line segment PQ as width, draw two arcs one above the line and one below the line.<\/span><\/p>\n<p><span style=\"font-weight: 400;\"><strong>Step 3:<\/strong>\u00a0Repeat the step above with Q as the centre.<\/span><\/p>\n<p><span style=\"font-weight: 400;\"><strong>Step 4: <\/strong>\u00a0Label the points of intersection as A and B.<\/span><\/p>\n<p><span style=\"font-weight: 400;\"><strong>Step 5: <\/strong>\u00a0Join the points A and B. This line segment AB is the perpendicular bisector. AB intersects the line segment PQ at its midpoint.<\/span><\/p>\n<p><span style=\"font-weight: 400;\"><\/span><\/p>\n<p><span style=\"font-weight: 400;\"><b>PERPENDICULAR BISECTOR OF A TRIANGLE<\/b><b><br \/><\/b><\/span><\/p>\n<p><span style=\"font-weight: 400;\">The perpendicular bisector of a triangle is a line segment that bisects the side of a triangle and passes through the midpoint of the side. It is perpendicular at the midpoint of the side of the triangle. We can draw perpendicular bisectors for all three sides of a triangle. When we draw the three perpendicular bisectors, they meet at a point which is called the circumcentre of the triangle.\u00a0<\/span><\/p>\n<p><span style=\"font-weight: 400;\">It is very easy to draw the perpendicular bisector of a side of a triangle if we know how to draw one for a line segment. We have a triangle ABC and we want to draw the perpendicular bisector of the line segment BC. We will do so in the following steps \u2013<\/span><\/p>\n<p><span style=\"font-weight: 400;\"><\/span><\/p>\n<p style=\"text-align: center;\"><span style=\"font-weight: 400;\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/eistudymaterial.s3.amazonaws.com\/A-perpendicular-bisector-01-217x300.png\" width=\"351\" height=\"485\" alt=\"\" class=\"wp-image-5967 alignnone size-medium\" srcset=\"https:\/\/eistudymaterial.s3.amazonaws.com\/A-perpendicular-bisector-01-217x300.png 217w, https:\/\/eistudymaterial.s3.amazonaws.com\/A-perpendicular-bisector-01.png 295w\" sizes=\"(max-width: 351px) 100vw, 351px\" \/><\/span><\/p>\n<p><span style=\"font-weight: 400;\"><\/span><\/p>\n<p><span style=\"font-weight: 400;\"><strong>Step 1:<\/strong> Take B as a centre and more than half of the length of BC as radius. Use the compass to draw arcs above and below the line segment BC and repeat the same process with C as the centre. We can label the points as P and Q. When we join P and Q, we get the perpendicular bisector of one side of the triangle BC.\u00a0<\/span><\/p>\n<p><span style=\"font-weight: 400;\"><strong>Step 2:<\/strong> Repeat the process for the other sides AB and AC to get the perpendicular bisectors of the other two sides.\u00a0<\/span><\/p>\n<p><span style=\"font-weight: 400;\">The point of intersection of the respective perpendicular bisector on each side is the midpoint of that side. 90\u00b0 angle is formed at the midpoints.<\/span><\/p>\n<p>[\/et_pb_text][\/et_pb_column][et_pb_column type=&#8221;2_5&#8243; module_id=&#8221;stickysideR&#8221; admin_label=&#8221;Column R&#8221; _builder_version=&#8221;4.10.4&#8243; _module_preset=&#8221;default&#8221; background_color=&#8221;#fdefe0&#8243; custom_padding=&#8221;25px|25px|25px|25px|true|true&#8221; sticky_position=&#8221;top&#8221; sticky_offset_top=&#8221;-280px&#8221; sticky_limit_top=&#8221;row&#8221; sticky_limit_bottom=&#8221;row&#8221; sticky_position_tablet=&#8221;none&#8221; sticky_position_phone=&#8221;none&#8221; sticky_position_last_edited=&#8221;on|desktop&#8221; sticky_limit_bottom_tablet=&#8221;&#8221; sticky_limit_bottom_phone=&#8221;&#8221; sticky_limit_bottom_last_edited=&#8221;on|phone&#8221; border_radii=&#8221;on|15px|15px|15px|15px&#8221; box_shadow_style=&#8221;preset3&#8243; global_colors_info=&#8221;{}&#8221;][et_pb_image src=&#8221;https:\/\/eistudymaterial.s3.amazonaws.com\/1080&#215;1080.png&#8221; alt=&#8221;Free Trial banner&#8221; title_text=&#8221;Mindspark Free Trial Banner&#8221; url=&#8221;https:\/\/mindspark.in\/free-trial&#8221; align=&#8221;center&#8221; module_class=&#8221;adsimg&#8221; _builder_version=&#8221;4.11.1&#8243; _module_preset=&#8221;default&#8221; custom_padding=&#8221;||||false|false&#8221; border_radii=&#8221;on|10px|10px|10px|10px&#8221; global_colors_info=&#8221;{}&#8221; transform_styles__hover_enabled=&#8221;on|hover&#8221; transform_scale__hover_enabled=&#8221;on|hover&#8221; transform_translate__hover_enabled=&#8221;on|desktop&#8221; transform_rotate__hover_enabled=&#8221;on|desktop&#8221; transform_skew__hover_enabled=&#8221;on|desktop&#8221; transform_origin__hover_enabled=&#8221;on|desktop&#8221; transform_scale__hover=&#8221;102%|102%&#8221;][\/et_pb_image][et_pb_text admin_label=&#8221;Explore Other Topics<br \/>\n&#8221; _builder_version=&#8221;4.9.11&#8243; _module_preset=&#8221;default&#8221; header_font=&#8221;|700|||||||&#8221; header_font_size=&#8221;25px&#8221; text_orientation=&#8221;center&#8221; custom_margin=&#8221;0px||0px||true|false&#8221; custom_padding=&#8221;8px|15px|0px|15px|false|true&#8221; locked=&#8221;off&#8221; global_colors_info=&#8221;{}&#8221;]<\/p>\n<h1>Explore Other Topics<\/h1>\n<p>[\/et_pb_text][et_pb_text _builder_version=&#8221;4.10.7&#8243; _module_preset=&#8221;default&#8221; text_line_height=&#8221;2.2em&#8221; link_font_size=&#8221;16px&#8221; custom_margin=&#8221;||0px||false|false&#8221; custom_padding=&#8221;10px|15px|10px|28px|true|false&#8221; locked=&#8221;off&#8221; global_colors_info=&#8221;{}&#8221;]<\/p>\n<div>\n<div class=\"trr\"><a href=\"https:\/\/stgwebsite.mindspark.in\/wordpress\/math-concepts\/#geometry\" class=\"otherc\">Geometry<\/a><\/div>\n<div class=\"trr\"><a href=\"https:\/\/stgwebsite.mindspark.in\/wordpress\/math-concepts\/#trigonometry\" class=\"otherc\">Trigonometry<\/a><\/div>\n<div class=\"trr\"><a href=\"https:\/\/stgwebsite.mindspark.in\/wordpress\/math-concepts\/#operations\" class=\"otherc\">Operations<\/a><\/div>\n<div class=\"trr\"><a href=\"https:\/\/stgwebsite.mindspark.in\/wordpress\/math-concepts\/#numbers\" class=\"otherc\">Numbers<\/a><\/div>\n<\/div>\n<p>[\/et_pb_text][et_pb_text admin_label=&#8221;Related Concepts<br \/>\n&#8221; _builder_version=&#8221;4.9.11&#8243; _module_preset=&#8221;default&#8221; header_font=&#8221;|700|||||||&#8221; header_font_size=&#8221;25px&#8221; text_orientation=&#8221;center&#8221; custom_margin=&#8221;0px||0px||true|false&#8221; custom_padding=&#8221;8px|15px|0px|15px|false|true&#8221; locked=&#8221;off&#8221; global_colors_info=&#8221;{}&#8221;]<\/p>\n<h1>Related Concepts<\/h1>\n<p>[\/et_pb_text][et_pb_text _builder_version=&#8221;4.13.1&#8243; _module_preset=&#8221;default&#8221; text_line_height=&#8221;2.2em&#8221; link_font_size=&#8221;16px&#8221; custom_margin=&#8221;||0px||false|false&#8221; custom_padding=&#8221;10px|15px|10px|28px|true|false&#8221; locked=&#8221;off&#8221; global_colors_info=&#8221;{}&#8221;]<\/p>\n<div class=\"trr\"><a href=\"https:\/\/mindspark.in\/studymaterial\/math-concepts\/concurrent-lines-point-of-concurrency-examples\/\" class=\"otherc\">Concurrent Lines<\/a><\/div>\n<div class=\"trr\"><a href=\"https:\/\/mindspark.in\/studymaterial\/math-concepts\/altitude-of-a-triangle-with-examples-and-faqs\/\" class=\"otherc\">Altitude of Triangle<\/a><\/div>\n<div class=\"trr\"><a href=\"https:\/\/mindspark.in\/studymaterial\/math-concepts\/circumcentre-of-a-triangle-distance-formula\/\" class=\"otherc\">Circumcentre of Triangle<\/a><\/div>\n<p>[\/et_pb_text][\/et_pb_column][\/et_pb_row][et_pb_row admin_label=&#8221;Row for space&#8221; _builder_version=&#8221;4.10.6&#8243; _module_preset=&#8221;default&#8221; locked=&#8221;off&#8221; global_colors_info=&#8221;{}&#8221;][et_pb_column type=&#8221;4_4&#8243; _builder_version=&#8221;4.9.11&#8243; _module_preset=&#8221;default&#8221; global_colors_info=&#8221;{}&#8221;][et_pb_divider show_divider=&#8221;off&#8221; _builder_version=&#8221;4.10.4&#8243; _module_preset=&#8221;default&#8221; global_colors_info=&#8221;{}&#8221;][\/et_pb_divider][\/et_pb_column][\/et_pb_row][\/et_pb_section][et_pb_section fb_built=&#8221;1&#8243; admin_label=&#8221;banner and faq Section&#8221; module_class=&#8221;mainsec2&#8243; _builder_version=&#8221;4.10.4&#8243; _module_preset=&#8221;default&#8221; custom_padding=&#8221;40px||0px||false|false&#8221; global_colors_info=&#8221;{}&#8221;][et_pb_row use_custom_gutter=&#8221;on&#8221; gutter_width=&#8221;1&#8243; make_equal=&#8221;on&#8221; disabled_on=&#8221;on|on|off&#8221; admin_label=&#8221;banner Row&#8221; _builder_version=&#8221;4.10.4&#8243; _module_preset=&#8221;default&#8221; background_color=&#8221;#fff7d6&#8243; width=&#8221;100%&#8221; max_width=&#8221;1310px&#8221; height=&#8221;134px&#8221; custom_margin=&#8221;||50px||false|false&#8221; custom_padding=&#8221;12px||12px||true|false&#8221; border_radii=&#8221;on|11px|11px|11px|11px&#8221; locked=&#8221;off&#8221; collapsed=&#8221;off&#8221; global_colors_info=&#8221;{}&#8221;][et_pb_column type=&#8221;4_4&#8243; _builder_version=&#8221;4.9.10&#8243; _module_preset=&#8221;default&#8221; global_colors_info=&#8221;{}&#8221;][et_pb_image src=&#8221;https:\/\/stgwebsite.mindspark.in\/wordpress\/wp-content\/uploads\/2021\/08\/calloutImage.png&#8221; title_text=&#8221;calloutImage&#8221; show_bottom_space=&#8221;off&#8221; admin_label=&#8221;Image&#8221; module_class=&#8221;img1&#8243; _builder_version=&#8221;4.10.8&#8243; _module_preset=&#8221;default&#8221; width=&#8221;25px&#8221; height=&#8221;60px&#8221; custom_padding=&#8221;2px||2px||true|false&#8221; global_colors_info=&#8221;{}&#8221;][\/et_pb_image][et_pb_text module_class=&#8221;ftstyle&#8221; _builder_version=&#8221;4.9.10&#8243; _module_preset=&#8221;default&#8221; text_orientation=&#8221;center&#8221; global_colors_info=&#8221;{}&#8221;]<\/p>\n<div class=\"ffmanage\">\n<div class=\"textmanagestyle\">\n<div class=\"fone\">\n<p>Ready to get started ?<\/p>\n<\/div>\n<div class=\"sone\">\n<p class=\"ffbtn\"><a href=\"https:\/\/mindspark.in\/free-trial\">Start Free Trial<\/a><\/p>\n<\/div>\n<\/div>\n<\/div>\n<p>[\/et_pb_text][et_pb_image src=&#8221;https:\/\/stgwebsite.mindspark.in\/wordpress\/wp-content\/uploads\/2021\/08\/down-circle.png&#8221; title_text=&#8221;down-circle&#8221; show_bottom_space=&#8221;off&#8221; align=&#8221;right&#8221; module_class=&#8221;img2&#8243; _builder_version=&#8221;4.9.10&#8243; _module_preset=&#8221;default&#8221; width=&#8221;44px&#8221; height=&#8221;18px&#8221; custom_padding=&#8221;2px||2px||true|false&#8221; global_colors_info=&#8221;{}&#8221;][\/et_pb_image][\/et_pb_column][\/et_pb_row][et_pb_row admin_label=&#8221;FAQ Row&#8221; _builder_version=&#8221;4.9.11&#8243; _module_preset=&#8221;default&#8221; width=&#8221;100%&#8221; max_width=&#8221;1310px&#8221; custom_padding=&#8221;|40px||40px|false|true&#8221; global_colors_info=&#8221;{}&#8221;][et_pb_column type=&#8221;4_4&#8243; _builder_version=&#8221;4.9.11&#8243; _module_preset=&#8221;default&#8221; global_colors_info=&#8221;{}&#8221;][et_pb_text admin_label=&#8221;FAQ&#8221; module_class=&#8221;faqstyl&#8221; _builder_version=&#8221;4.13.1&#8243; _module_preset=&#8221;default&#8221; text_font_size=&#8221;16px&#8221; header_font=&#8221;|700|||||||&#8221; header_text_align=&#8221;center&#8221; header_line_height=&#8221;2.5em&#8221; background_color=&#8221;#dbedc6&#8243; max_width=&#8221;80%&#8221; module_alignment=&#8221;center&#8221; custom_margin=&#8221;||||false|false&#8221; custom_padding=&#8221;30px|25px|30px|25px|true|true&#8221; border_radii=&#8221;on|10px|10px|10px|10px&#8221; global_colors_info=&#8221;{}&#8221;]<\/p>\n<h1>Frequently Asked Questions<span style=\"font-weight: 400;\"><span style=\"font-weight: 400;\">\u00a0<\/span><\/span><\/h1>\n<ol><\/ol>\n<h3><strong>Q1. What is a perpendicular bisector?<br \/><\/strong><\/h3>\n<p><span style=\"font-weight: 400;\"><strong>Ans: <\/strong>The perpendicular bisector is a line segment that divides a line segment or a triangle into two congruent parts.<strong><br \/><\/strong><\/span><span style=\"font-weight: 400;\"><\/span><\/p>\n<h3><strong>Q2. What will be the point at which a perpendicular bisector will divide a line segment of 12 cm?<br \/><\/strong><\/h3>\n<p><strong>Ans: <\/strong>Since a perpendicular bisector divides the line segment into two equal parts, so the perpendicular bisector divides the line segment at exactly 6 cm.<\/p>\n<h3><strong>Q3. Where will be the circumcentre of an obtuse triangle?<\/strong><\/h3>\n<p><strong>Ans: <\/strong><span style=\"font-weight: 400;\">An obtuse triangle is a triangle that has one of the angles as obtuse angles. The circumcentre of the obtuse triangle lies outside the triangle.<\/span><\/p>\n<p><strong>\u00a0<\/strong><\/p>\n<p>[\/et_pb_text][\/et_pb_column][\/et_pb_row][\/et_pb_section]<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Meta Description: We can calculate the sum of the terms in a geometric progression using the formula  S = a(1-r^n)\/(1-r) when r < 1 and  S = a(r^n-1)\/(r-1)when r>1<\/p>\n","protected":false},"author":10,"featured_media":0,"parent":714,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"","meta":{"_et_pb_use_builder":"on","_et_pb_old_content":"","_et_gb_content_width":"","footnotes":""},"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v17.6 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>WHAT IS A PERPENDICULAR BISECTOR - mydomain<\/title>\n<meta name=\"description\" content=\"Meta Description: We can calculate the sum of the terms in a geometric progression using the formula S = a(1-r^n)\/(1-r) when r &lt; 1 and S = a(r^n-1)\/(r-1)when r&gt;1\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/stgwebsite.mindspark.in\/studymaterial\/math-concepts\/what-is-a-perpendicular-bisector\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"WHAT IS A PERPENDICULAR BISECTOR - mydomain\" \/>\n<meta property=\"og:description\" content=\"Meta Description: We can calculate the sum of the terms in a geometric progression using the formula S = a(1-r^n)\/(1-r) when r &lt; 1 and S = a(r^n-1)\/(r-1)when r&gt;1\" \/>\n<meta property=\"og:url\" content=\"https:\/\/stgwebsite.mindspark.in\/studymaterial\/math-concepts\/what-is-a-perpendicular-bisector\/\" \/>\n<meta property=\"og:site_name\" content=\"mydomain\" \/>\n<meta property=\"article:modified_time\" content=\"2022-01-03T08:07:02+00:00\" \/>\n<meta property=\"og:image\" content=\"https:\/\/eistudymaterial.s3.amazonaws.com\/ap-283x300.jpg\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data1\" content=\"4 minutes\" \/>\n<script type=\"application\/ld+json\" class=\"yoast-schema-graph\">{\"@context\":\"https:\/\/schema.org\",\"@graph\":[{\"@type\":\"WebSite\",\"@id\":\"https:\/\/stgwebsite.mindspark.in\/studymaterial\/#website\",\"url\":\"https:\/\/stgwebsite.mindspark.in\/studymaterial\/\",\"name\":\"mydomain\",\"description\":\"Just another WordPress site\",\"potentialAction\":[{\"@type\":\"SearchAction\",\"target\":{\"@type\":\"EntryPoint\",\"urlTemplate\":\"https:\/\/stgwebsite.mindspark.in\/studymaterial\/?s={search_term_string}\"},\"query-input\":\"required name=search_term_string\"}],\"inLanguage\":\"en-US\"},{\"@type\":\"ImageObject\",\"@id\":\"https:\/\/stgwebsite.mindspark.in\/studymaterial\/math-concepts\/what-is-a-perpendicular-bisector\/#primaryimage\",\"inLanguage\":\"en-US\",\"url\":\"https:\/\/eistudymaterial.s3.amazonaws.com\/ap-283x300.jpg\",\"contentUrl\":\"https:\/\/eistudymaterial.s3.amazonaws.com\/ap-283x300.jpg\"},{\"@type\":\"WebPage\",\"@id\":\"https:\/\/stgwebsite.mindspark.in\/studymaterial\/math-concepts\/what-is-a-perpendicular-bisector\/#webpage\",\"url\":\"https:\/\/stgwebsite.mindspark.in\/studymaterial\/math-concepts\/what-is-a-perpendicular-bisector\/\",\"name\":\"WHAT IS A PERPENDICULAR BISECTOR - mydomain\",\"isPartOf\":{\"@id\":\"https:\/\/stgwebsite.mindspark.in\/studymaterial\/#website\"},\"primaryImageOfPage\":{\"@id\":\"https:\/\/stgwebsite.mindspark.in\/studymaterial\/math-concepts\/what-is-a-perpendicular-bisector\/#primaryimage\"},\"datePublished\":\"2021-12-16T03:41:02+00:00\",\"dateModified\":\"2022-01-03T08:07:02+00:00\",\"description\":\"Meta Description: We can calculate the sum of the terms in a geometric progression using the formula S = a(1-r^n)\/(1-r) when r < 1 and S = a(r^n-1)\/(r-1)when r>1\",\"breadcrumb\":{\"@id\":\"https:\/\/stgwebsite.mindspark.in\/studymaterial\/math-concepts\/what-is-a-perpendicular-bisector\/#breadcrumb\"},\"inLanguage\":\"en-US\",\"potentialAction\":[{\"@type\":\"ReadAction\",\"target\":[\"https:\/\/stgwebsite.mindspark.in\/studymaterial\/math-concepts\/what-is-a-perpendicular-bisector\/\"]}]},{\"@type\":\"BreadcrumbList\",\"@id\":\"https:\/\/stgwebsite.mindspark.in\/studymaterial\/math-concepts\/what-is-a-perpendicular-bisector\/#breadcrumb\",\"itemListElement\":[{\"@type\":\"ListItem\",\"position\":1,\"name\":\"Home\",\"item\":\"https:\/\/stgwebsite.mindspark.in\/studymaterial\/\"},{\"@type\":\"ListItem\",\"position\":2,\"name\":\"Math Concepts\",\"item\":\"https:\/\/stgwebsite.mindspark.in\/studymaterial\/math-concepts\/\"},{\"@type\":\"ListItem\",\"position\":3,\"name\":\"WHAT IS A PERPENDICULAR BISECTOR\"}]}]}<\/script>\n<!-- \/ Yoast SEO plugin. -->","yoast_head_json":{"title":"WHAT IS A PERPENDICULAR BISECTOR - mydomain","description":"Meta Description: We can calculate the sum of the terms in a geometric progression using the formula S = a(1-r^n)\/(1-r) when r < 1 and S = a(r^n-1)\/(r-1)when r>1","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/stgwebsite.mindspark.in\/studymaterial\/math-concepts\/what-is-a-perpendicular-bisector\/","og_locale":"en_US","og_type":"article","og_title":"WHAT IS A PERPENDICULAR BISECTOR - mydomain","og_description":"Meta Description: We can calculate the sum of the terms in a geometric progression using the formula S = a(1-r^n)\/(1-r) when r < 1 and S = a(r^n-1)\/(r-1)when r>1","og_url":"https:\/\/stgwebsite.mindspark.in\/studymaterial\/math-concepts\/what-is-a-perpendicular-bisector\/","og_site_name":"mydomain","article_modified_time":"2022-01-03T08:07:02+00:00","og_image":[{"url":"https:\/\/eistudymaterial.s3.amazonaws.com\/ap-283x300.jpg"}],"twitter_card":"summary_large_image","twitter_misc":{"Est. reading time":"4 minutes"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"WebSite","@id":"https:\/\/stgwebsite.mindspark.in\/studymaterial\/#website","url":"https:\/\/stgwebsite.mindspark.in\/studymaterial\/","name":"mydomain","description":"Just another WordPress site","potentialAction":[{"@type":"SearchAction","target":{"@type":"EntryPoint","urlTemplate":"https:\/\/stgwebsite.mindspark.in\/studymaterial\/?s={search_term_string}"},"query-input":"required name=search_term_string"}],"inLanguage":"en-US"},{"@type":"ImageObject","@id":"https:\/\/stgwebsite.mindspark.in\/studymaterial\/math-concepts\/what-is-a-perpendicular-bisector\/#primaryimage","inLanguage":"en-US","url":"https:\/\/eistudymaterial.s3.amazonaws.com\/ap-283x300.jpg","contentUrl":"https:\/\/eistudymaterial.s3.amazonaws.com\/ap-283x300.jpg"},{"@type":"WebPage","@id":"https:\/\/stgwebsite.mindspark.in\/studymaterial\/math-concepts\/what-is-a-perpendicular-bisector\/#webpage","url":"https:\/\/stgwebsite.mindspark.in\/studymaterial\/math-concepts\/what-is-a-perpendicular-bisector\/","name":"WHAT IS A PERPENDICULAR BISECTOR - mydomain","isPartOf":{"@id":"https:\/\/stgwebsite.mindspark.in\/studymaterial\/#website"},"primaryImageOfPage":{"@id":"https:\/\/stgwebsite.mindspark.in\/studymaterial\/math-concepts\/what-is-a-perpendicular-bisector\/#primaryimage"},"datePublished":"2021-12-16T03:41:02+00:00","dateModified":"2022-01-03T08:07:02+00:00","description":"Meta Description: We can calculate the sum of the terms in a geometric progression using the formula S = a(1-r^n)\/(1-r) when r < 1 and S = a(r^n-1)\/(r-1)when r>1","breadcrumb":{"@id":"https:\/\/stgwebsite.mindspark.in\/studymaterial\/math-concepts\/what-is-a-perpendicular-bisector\/#breadcrumb"},"inLanguage":"en-US","potentialAction":[{"@type":"ReadAction","target":["https:\/\/stgwebsite.mindspark.in\/studymaterial\/math-concepts\/what-is-a-perpendicular-bisector\/"]}]},{"@type":"BreadcrumbList","@id":"https:\/\/stgwebsite.mindspark.in\/studymaterial\/math-concepts\/what-is-a-perpendicular-bisector\/#breadcrumb","itemListElement":[{"@type":"ListItem","position":1,"name":"Home","item":"https:\/\/stgwebsite.mindspark.in\/studymaterial\/"},{"@type":"ListItem","position":2,"name":"Math Concepts","item":"https:\/\/stgwebsite.mindspark.in\/studymaterial\/math-concepts\/"},{"@type":"ListItem","position":3,"name":"WHAT IS A PERPENDICULAR BISECTOR"}]}]}},"_links":{"self":[{"href":"https:\/\/stgwebsite.mindspark.in\/studymaterial\/wp-json\/wp\/v2\/pages\/5963"}],"collection":[{"href":"https:\/\/stgwebsite.mindspark.in\/studymaterial\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/stgwebsite.mindspark.in\/studymaterial\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/stgwebsite.mindspark.in\/studymaterial\/wp-json\/wp\/v2\/users\/10"}],"replies":[{"embeddable":true,"href":"https:\/\/stgwebsite.mindspark.in\/studymaterial\/wp-json\/wp\/v2\/comments?post=5963"}],"version-history":[{"count":5,"href":"https:\/\/stgwebsite.mindspark.in\/studymaterial\/wp-json\/wp\/v2\/pages\/5963\/revisions"}],"predecessor-version":[{"id":7679,"href":"https:\/\/stgwebsite.mindspark.in\/studymaterial\/wp-json\/wp\/v2\/pages\/5963\/revisions\/7679"}],"up":[{"embeddable":true,"href":"https:\/\/stgwebsite.mindspark.in\/studymaterial\/wp-json\/wp\/v2\/pages\/714"}],"wp:attachment":[{"href":"https:\/\/stgwebsite.mindspark.in\/studymaterial\/wp-json\/wp\/v2\/media?parent=5963"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}