{"id":7085,"date":"2021-12-29T08:00:04","date_gmt":"2021-12-29T08:00:04","guid":{"rendered":"https:\/\/stgwebsite.mindspark.in\/studymaterial\/?page_id=7085"},"modified":"2022-01-03T06:49:47","modified_gmt":"2022-01-03T06:49:47","slug":"area-of-an-isosceles-right-triangle","status":"publish","type":"page","link":"https:\/\/stgwebsite.mindspark.in\/studymaterial\/math-concepts\/area-of-an-isosceles-right-triangle\/","title":{"rendered":"Area of an isosceles right triangle"},"content":{"rendered":"<p>[et_pb_section fb_built=&#8221;1&#8243; admin_label=&#8221;Section&#8221; module_class=&#8221;mainsec&#8221; _builder_version=&#8221;4.10.4&#8243; _module_preset=&#8221;default&#8221; background_color=&#8221;#e0f2fd&#8221; z_index=&#8221;1&#8243; custom_padding=&#8221;5px||5px||true|false&#8221; locked=&#8221;off&#8221; collapsed=&#8221;off&#8221; global_colors_info=&#8221;{}&#8221;][et_pb_row column_structure=&#8221;3_5,2_5&#8243; custom_padding_last_edited=&#8221;on|phone&#8221; _builder_version=&#8221;4.10.8&#8243; _module_preset=&#8221;default&#8221; background_color=&#8221;#FFFFFF&#8221; width=&#8221;100%&#8221; max_width=&#8221;1310px&#8221; custom_padding=&#8221;|51px|40px|51px|false|true&#8221; custom_padding_tablet=&#8221;&#8221; custom_padding_phone=&#8221;|40px|30px|40px|false|true&#8221; border_radii=&#8221;on|10px|10px|10px|10px&#8221; global_colors_info=&#8221;{}&#8221;][et_pb_column type=&#8221;3_5&#8243; admin_label=&#8221;Column L&#8221; _builder_version=&#8221;4.9.10&#8243; _module_preset=&#8221;default&#8221; global_colors_info=&#8221;{}&#8221;][et_pb_text admin_label=&#8221;Acute Angles<br \/>\n&#8221; _builder_version=&#8221;4.11.3&#8243; _module_preset=&#8221;default&#8221; header_font=&#8221;|700|||||||&#8221; header_text_align=&#8221;left&#8221; header_font_size=&#8221;50px&#8221; header_line_height=&#8221;1.18em&#8221; custom_padding=&#8221;|0px||4px|false|false&#8221; header_font_size_tablet=&#8221;&#8221; header_font_size_phone=&#8221;35px&#8221; header_font_size_last_edited=&#8221;on|phone&#8221; global_colors_info=&#8221;{}&#8221;]<\/p>\n<h1>Area of an isosceles right triangle<\/h1>\n<p>[\/et_pb_text][et_pb_text admin_label=&#8221;Text&#8221; _builder_version=&#8221;4.13.1&#8243; _module_preset=&#8221;default&#8221; text_font_size=&#8221;16px&#8221; header_2_font=&#8221;|600|||||||&#8221; header_2_text_color=&#8221;#a01414&#8243; header_3_font=&#8221;|600|||||||&#8221; custom_padding=&#8221;15px|15px|54px|4px|false|false&#8221; global_colors_info=&#8221;{}&#8221;]<\/p>\n<h2><b>Area of isosceles right triangle<\/b><\/h2>\n<p>It is the area enclosed by the three sides of the isosceles right triangle.<\/p>\n<p>In the figure given below, it is the area shaded in yellow.<\/p>\n<p>&nbsp;<\/p>\n<h2><b>What is an Isosceles right triangle?<\/b><\/h2>\n<p><span style=\"font-weight: 400;\">A triangle consisting of a right triangle is known as a right-angled triangle. When the two sides of this triangle other than the hypotenuse are equal, it is the isosceles right triangle.<\/span><\/p>\n<p><span style=\"font-weight: 400;\"><\/span><\/p>\n<p style=\"text-align: center;\"><span style=\"font-weight: 400;\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/eistudymaterial.s3.amazonaws.com\/Area-of-isosceles-right-triangle-01.png\" width=\"250\" height=\"292\" alt=\"\" class=\"wp-image-7088 alignnone size-full\" \/><\/span><\/p>\n<p><span style=\"font-weight: 400;\">In \u25b3ABC,<\/span><\/p>\n<ol>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-weight: 400;\">\u2220ABC = 90\u00b0<\/span><\/li>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-weight: 400;\">AB = BC = legs = a<\/span><\/li>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-weight: 400;\">AC = hypotenuse = b<\/span><\/li>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-weight: 400;\">\u2220BAC = \u2220ACB = 45\u00b0<\/span><\/li>\n<\/ol>\n<p><span style=\"font-weight: 400;\">Hence it is an isosceles right triangle<\/span><\/p>\n<p>&nbsp;<\/p>\n<h2><b>The formula for finding the area<\/b><\/h2>\n<p><b><span style=\"font-weight: 400;\">Area =<span class=\"katex-eq\" data-katex-display=\"false\">\\frac{1}{2} a^{2}<\/span><\/span><\/b><\/p>\n<p><span style=\"font-weight: 400;\">Where a = length of a leg<\/span><\/p>\n<p><span style=\"font-weight: 400;\"><\/span><\/p>\n<h2><b>Derivation of the formula<\/b><\/h2>\n<p style=\"text-align: center;\"><b><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/eistudymaterial.s3.amazonaws.com\/Area-of-isosceles-right-triangle-01.png\" width=\"250\" height=\"292\" alt=\"\" class=\"wp-image-7088 alignnone size-full\" \/><\/b><\/p>\n<p><span style=\"font-weight: 400;\">We already know that the area of a triangle is given by the following formula<\/span><\/p>\n<p><span style=\"font-weight: 400;\"><span class=\"katex-eq\" data-katex-display=\"false\">\\text { Area }=\\frac{1}{2} \\times \\text { base } \\times \\text { height }<\/span><\/span><\/p>\n<p><span style=\"font-weight: 400;\">In \u25b3ABC, <\/span><span style=\"font-weight: 400;\">\u2220ABC = 90\u00b0<\/span><\/p>\n<p><span style=\"font-weight: 400;\">Hence BC is the base and AB is the height of the triangle.<\/span><\/p>\n<p><span style=\"font-weight: 400;\">Base = BC = a\u00a0<\/span><\/p>\n<p><span style=\"font-weight: 400;\">Height = AB = a\u00a0<\/span><\/p>\n<p><span style=\"font-weight: 400;\"><span class=\"katex-eq\" data-katex-display=\"false\">\\text { Area of } \\triangle \\mathrm{ABC}<\/span><\/span><\/p>\n<p><span style=\"font-weight: 400;\"><\/span><\/p>\n<p><span style=\"font-weight: 400;\"><span class=\"katex-eq\" data-katex-display=\"false\">=\\frac{1}{2} \\times \\text { base } \\times \\text { height } <\/span><\/span><\/p>\n<p><span style=\"font-weight: 400;\"><br \/><span class=\"katex-eq\" data-katex-display=\"false\">=\\frac{1}{2} \\times \\mathrm{BC} \\times \\mathrm{AB} <\/span><\/span><\/p>\n<p><span style=\"font-weight: 400;\"><br \/><span class=\"katex-eq\" data-katex-display=\"false\">=\\frac{1}{2} \\times \\mathrm{a} \\times \\mathrm{a}<\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"font-weight: 400;\"><span class=\"katex-eq\" data-katex-display=\"false\">=\\frac{1}{2} \\times a^{2}<\/span><\/span><\/p>\n<p><span style=\"font-weight: 400;\">Hence it is proved that the area of an isosceles right triangle is\u00a0 <span class=\"katex-eq\" data-katex-display=\"false\">\\frac{1}{2} a^{2}<\/span>, <\/span><span style=\"font-weight: 400;\">where a is the length of the leg of the triangle.<\/span><\/p>\n<p><span style=\"font-weight: 400;\"><\/span><\/p>\n<h2><b>Solved Examples.<\/b><\/h2>\n<p><b><\/b><\/p>\n<p><b>1. In a right-angled triangle, two sides are equal, having a length of 7 cm. Find the area of this triangle?<\/b><\/p>\n<p><strong>Solution:<\/strong><\/p>\n<p><span style=\"font-weight: 400;\">Since two sides of the right-angled triangle are equal, it is an isosceles right triangle.<\/span><\/p>\n<p><span style=\"font-weight: 400;\">Length of the leg = a = 7 cm<\/span><\/p>\n<p><span style=\"font-weight: 400;\"><span class=\"katex-eq\" data-katex-display=\"false\">\\text { Area of the right- angled triangle }<\/span><\/span><\/p>\n<p><span style=\"font-weight: 400;\"><\/span><\/p>\n<p><span style=\"font-weight: 400;\"><span class=\"katex-eq\" data-katex-display=\"false\">=\\frac{1}{2} \\times a^{2} <\/span><\/span><\/p>\n<p><span style=\"font-weight: 400;\"><br \/><span class=\"katex-eq\" data-katex-display=\"false\">=\\left(\\frac{1}{2} \\times 7^{2}\\right) \\mathrm{cm}^{2} <\/span><\/span><\/p>\n<p><span style=\"font-weight: 400;\"><br \/><span class=\"katex-eq\" data-katex-display=\"false\">=\\left(\\frac{1}{2} \\times 49\\right) \\mathrm{cm}^{2} <\/span><\/span><\/p>\n<p><span style=\"font-weight: 400;\"><br \/><span class=\"katex-eq\" data-katex-display=\"false\">=24.5 \\mathrm{~cm}^{2}<\/span><\/span><\/p>\n<p>\u00a0<span style=\"font-weight: 400;\">The area of this triangle is <span class=\"katex-eq\" data-katex-display=\"false\">24.5 \\mathrm{~cm}^{2}<\/span><br \/><\/span><\/p>\n<p><span style=\"font-weight: 400;\"><\/span><\/p>\n<p><b>2. The area of a triangle is 18 cm<\/b><b>\u00b2<\/b><b>. What is the length of the hypotenuse if it is an isosceles right triangle?<\/b><\/p>\n<p><strong>Solution:<\/strong><\/p>\n<p><span style=\"font-weight: 400;\">We know that\u00a0<\/span><\/p>\n<p><span style=\"font-weight: 400;\"><span class=\"katex-eq\" data-katex-display=\"false\">\\text { Area }=\\frac{1}{2} \\times a^{2}<\/span><\/span><\/p>\n<p><span style=\"font-weight: 400;\">Where a = length of the leg<\/span><\/p>\n<p><span style=\"font-weight: 400;\">It is given that<\/span><\/p>\n<p><span style=\"font-weight: 400;\"><span class=\"katex-eq\" data-katex-display=\"false\">\\text { Area }=18 \\mathrm{~cm}^{2}<\/span><\/span><\/p>\n<p><span style=\"font-weight: 400;\"><span class=\"katex-eq\" data-katex-display=\"false\">\\Rightarrow \\frac{1}{2} \\times a^{2}=18 <\/span><\/span><\/p>\n<p><span style=\"font-weight: 400;\"><br \/><span class=\"katex-eq\" data-katex-display=\"false\">\\Rightarrow a^{2}=18 \\times 2=36 <\/span><\/span><\/p>\n<p><span style=\"font-weight: 400;\"><br \/><span class=\"katex-eq\" data-katex-display=\"false\">\\Rightarrow a=\\sqrt{36}=6 \\mathrm{~cm}<\/span><\/span><\/p>\n<p><span style=\"font-weight: 400;\">Since two sides are equal in an isosceles right triangle, according to Pythagoras theorem we can write that<\/span><\/p>\n<p><span style=\"font-weight: 400;\"><span class=\"katex-eq\" data-katex-display=\"false\">{\\text{Side}} ^{2}+{\\text{Side}} ^{2}={\\text{hypotenuse}} ^{2}<\/span><\/span><\/p>\n<p><span style=\"font-weight: 400;\"><br \/><span class=\"katex-eq\" data-katex-display=\"false\">{\\text{Hypotenuse}} ^{2}=a^{2}+a^{2}=2 a^{2}=2 \\times 6^{2}=2 \\times 36=72<\/span><\/span><\/p>\n<p><span style=\"font-weight: 400;\"><br \/><span class=\"katex-eq\" data-katex-display=\"false\">{\\text{Hypotenuse}} =\\sqrt{72}=6 \\sqrt{2} \\mathrm{~cm}<\/span><\/span><\/p>\n<p><span style=\"font-weight: 400;\">Hence the length of the hypotenuse is 6<\/span><span style=\"font-weight: 400;\">\u221a2<\/span><span style=\"font-weight: 400;\"> cm.<\/span><\/p>\n<p>[\/et_pb_text][\/et_pb_column][et_pb_column type=&#8221;2_5&#8243; 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_module_preset=&#8221;default&#8221; width=&#8221;100%&#8221; max_width=&#8221;1310px&#8221; custom_padding=&#8221;|40px||40px|false|true&#8221; global_colors_info=&#8221;{}&#8221;][et_pb_column type=&#8221;4_4&#8243; _builder_version=&#8221;4.9.11&#8243; _module_preset=&#8221;default&#8221; global_colors_info=&#8221;{}&#8221;][et_pb_text admin_label=&#8221;FAQ&#8221; module_class=&#8221;faqstyl&#8221; _builder_version=&#8221;4.13.1&#8243; _module_preset=&#8221;default&#8221; text_font_size=&#8221;16px&#8221; header_font=&#8221;|700|||||||&#8221; header_text_align=&#8221;center&#8221; header_line_height=&#8221;2.5em&#8221; background_color=&#8221;#dbedc6&#8243; max_width=&#8221;80%&#8221; module_alignment=&#8221;center&#8221; custom_margin=&#8221;||||false|false&#8221; custom_padding=&#8221;30px|25px|30px|25px|true|true&#8221; border_radii=&#8221;on|10px|10px|10px|10px&#8221; global_colors_info=&#8221;{}&#8221;]<\/p>\n<h1>Frequently Asked Questions<span style=\"font-weight: 400;\"><span style=\"font-weight: 400;\">\u00a0<\/span><\/span><\/h1>\n<ol><\/ol>\n<h3><strong>Q1. What is an isosceles triangle?<br \/><\/strong><\/h3>\n<p><span style=\"font-weight: 400;\"><strong>Ans: <\/strong>It is the triangle having two sides equal.<strong><br \/><\/strong><\/span><span style=\"font-weight: 400;\"><\/span><\/p>\n<h3><strong>Q2. What is a right-angled triangle?<br \/><\/strong><\/h3>\n<p><strong>Ans: <\/strong>It is a triangle in which the measure of any one of the angles is 90\u00b0.<strong><br \/><\/strong><\/p>\n<h3><strong>Q3. 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